octave

问题 I have a 1xn struct. The structs contains some fields with numeric cells. Not every struct has the same fields. So I would like to add the missing fields to the struct. But I didn't get it. % Mimimal example % I have same cells, imported from csv by csv2cell() clear dataCell{1}={"field_a","field_b","field_c"; ... 1,2,3; ... 4,5,6}; dataCell{2}={"field_a","field_b","field_d"; ... 1,2,4; ... 4,5,8}; % Then I convert them to a struct for ii=1:numel(dataCell) DataStruct{ii}=cell2struct((dataCell

问题 I have a 1xn struct. The structs contains some fields with numeric cells. Not every struct has the same fields. So I would like to add the missing fields to the struct. But I didn't get it. % Mimimal example % I have same cells, imported from csv by csv2cell() clear dataCell{1}={"field_a","field_b","field_c"; ... 1,2,3; ... 4,5,6}; dataCell{2}={"field_a","field_b","field_d"; ... 1,2,4; ... 4,5,8}; % Then I convert them to a struct for ii=1:numel(dataCell) DataStruct{ii}=cell2struct((dataCell

问题 I found some sources online that indicate that there are tools for Octave that allow one to parallelize algorithms, but couldn't find any details or how to get and use them. Any help/insight into this would be great. 回答1: http://octave.sourceforge.net/parallel/ Just install the package and the function reference may help. 来源： https://stackoverflow.com/questions/7047840/parallel-computing-in-octave

问题 I'm using Octave and R to compute SVD using a simple matrix and getting two different answers! The code is listed below: R > a<-matrix(c(1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,1,1,1,0,0,0,0,0,0,0,0,0,1,1,1), 9, 4) > a [,1] [,2] [,3] [,4] [1,] 1 1 0 0 [2,] 1 1 0 0 [3,] 1 1 0 0 [4,] 1 0 1 0 [5,] 1 0 1 0 [6,] 1 0 1 0 [7,] 1 0 0 1 [8,] 1 0 0 1 [9,] 1 0 0 1 > a.svd <- svd(a) > a.svd$d [1] 3.464102e+00 1.732051e+00 1.732051e+00 1.922963e-16 > a.svd$u [,1] [,2] [,3] [,4] [1,] -0.3333333 0.4714045

问题 Is there a vectorised way to do the following? (shown by an example): input_lengths = [ 1 1 1 4 3 2 1 ] result = [ 1 2 3 4 4 4 4 5 5 5 6 6 7 ] I have spaced out the input_lengths so it is easy to understand how the result is obtained The resultant vector is of length: sum(lengths) . I currently calculate result using the following loop: result = ones(1, sum(input_lengths )); counter = 1; for i = 1:length(input_lengths) start_index = counter; end_index = counter + input_lengths (i) - 1; result

问题 Here is the context of the problem: I have a DTMF signal in wav format, I have to identify the number sequence it has encoded. I must do so using fast fourier transform in Matlab, implying that I read the wav file using wavread and to identify each number that is seperated by 40ms silence or more. Here is my code so far: [signal, fs] = wavread( 'C:\Temp\file.wav' ); % here, fs = 8000Hz N = 512; T = 1/fs; L = length( signal ) samples = fs / 1000 * 40 windows = floor(L / samples) t = (1:L)/fs;

问题 Is there a way in Octave to compute and store only the diagonal of a matrix product? Basically like doing: vector = diag(A*B); I don't care about any of the values of A*B except those on the diagonal. The matrix sizes are around 80k x 12 and 12 x 80k , so even if I didn't care about the speed/extra memory it simply wont fit in RAM. Strange, since Octave is a package for huge data sets and diagonals are very important, so it should be possible. 回答1: The first element in the diagonal is the

问题 I have tried to compile Octave 3.4.3 on Kubuntu 10.04 LTS on an AMD64 machine but make fails with the following error /bin/bash ../libtool --tag=F77 --mode=compile f77 -O -c -o arpack/src/libcruft_la-cgetv0.lo `test -f 'arpack/src/cgetv0.f' || echo './'`arpack/src/cgetv0.f libtool: compile: f77 -O -c arpack/src/cgetv0.f -fPIC -o arpack/src/.libs/libcruft_la-cgetv0.o cgetv0: Cannot open file debug.h /usr/bin/f77: aborting compilation make[2]: *** [arpack/src/libcruft_la-cgetv0.lo] Error 1 make

问题 I have a very basic custom boxplot function: function myboxplot(LPercentile, Median, RPercentile, Height, LineWidth, BoxHeight, MarkerColour, MarkerSize) hold on plot([LPercentile, RPercentile], [Height, Height], 'linewidth', LineWidth, 'color', 'k', 'linestyle', '-'); plot([LPercentile, LPercentile], [Height - BoxHeight/2, Height + BoxHeight/2], 'linewidth', LineWidth, 'color', 'k', 'linestyle', '-'); plot([RPercentile, RPercentile], [Height - BoxHeight/2, Height + BoxHeight/2], 'linewidth',

问题 I have a two column array of data. First column is time (date in decimal years) and second column is the signal strength. The plot is a triangle wave or should be ideally because the sampling is irregularly timed. I've tried numerous methods to get the period of the wave, including fitting a sine wave to the data via lsqcurvefit, but it doesn't always return the right period. Using OCTAVE how do I get the period (my main aim) of this/any irregularly-spaced time series?See plot 回答1: Found