setting multiple fields at once / add new field to a cell struct

问题

I have a 1xn struct. The structs contains some fields with numeric cells. Not every struct has the same fields. So I would like to add the missing fields to the struct. But I didn't get it.

%  Mimimal example
%  I have same cells, imported from csv by csv2cell()

clear

dataCell{1}={"field_a","field_b","field_c"; ...
    1,2,3; ...
    4,5,6};

dataCell{2}={"field_a","field_b","field_d"; ...
    1,2,4; ...
    4,5,8};

%   Then I convert them to a struct
for ii=1:numel(dataCell)    
DataStruct{ii}=cell2struct((dataCell{ii}(2:end,:)),[dataCell{ii}(1,:)],2);
  try fields=[fields, fieldnames(DataStruct{ii})']; % fails for the first loop, because 'fields' doesn't exist yet
  catch
   fields=[fieldnames(DataStruct{ii})']; % create 'fields' in the first loop
  end
end

% Create a list of all existing fields
fields=unique(fields);

% Now look for the missing fields and add them to the struct
for jj=1:numel(DataStruct)
  missing_fields{jj} = setdiff(fields,fieldnames(DataStruct{jj}));
  for kk=1:numel(missing_fields)
    DataStruct{jj}.(missing_fields{jj}{kk})=NaN*zeros(numel(dataCell{jj}(2:end,1)),1); % Execution fails here!
  end
end

This leads to an error:

Octave Error

error: invalid assignment to cs-list outside multiple assignment
error: called from:
error:   ~/example.m at line 29, column 44

Matlab Error

Insufficient outputs from right hand side to satisfy comma separated
list expansion on left hand side.  Missing [] are the most likely cause.

The problem is, that the output of DataStruct{1}.field_a is not a matrix or a cell, but multiple ans. Is there a easy possibility to convert the cells to a matrix or a better possibility to import the csv?

the other good possibility would be something like this

 DataStruct{jj}=setfields(missing_fields{jj},NaN_Values{jj})

where missing_fields{jj} and NaN_Values are both cells with the same length, so that i can set multiple fields at once.

回答1:

You use the deal function to distribute output to inputs. For your example:

% Now look for the missing fields and add them to the struct
for jj=1:numel(DataStruct)
  missing_fields{jj} = setdiff(fields,fieldnames(DataStruct{jj}));
  for kk=1:numel(missing_fields)
    [DataStruct{jj}.(missing_fields{jj}{kk})] = deal(NaN*zeros(numel(dataCell{jj}(2:end,1)),1));
  end
end

Note that you will get an Index exceeds matrix dimensions, but this is due to a different problem - I'm sure you'll be able to sort that one out!

回答2:

following your last question - you can use the deal command.

Snippet:

a=struct('f1',num2cell(1:10))
missing_field = 'test'
[a.(missing_field)]=deal(NaN)

来源：https://stackoverflow.com/questions/14870828/setting-multiple-fields-at-once-add-new-field-to-a-cell-struct

标签

matlab

octave