numberformatexception

I'm currently facing to a glitch from an Galaxy Tab 10.1 2 (GT-P5110) which give me that error, but just on that device. I tried on divers emulators (I use genymotion: Nexus 5-7-10, Galaxy S3-4-5, Galaxy Note 2-3) and devices (Galaxy S -2-3-4, Nexus 5-7). But just on that Galaxy tab 2 10.1 (GT-P5110) I have this error. I found this link , but this didn't really help me out to solve that problem. 07-01 11:06:58.832 14227-14227/com.********.********.com E/AndroidRuntime﹕ FATAL EXCEPTION: main android.view.InflateException: Binary XML file line #36: Error inflating class com.package.fr.views

This question already has answers here : What is a NumberFormatException and how can I fix it? [duplicate] (9 answers) Closed 3 years ago . I gave 23 (looks like a proper string) as input, but stil get NumberFormatException. Please point out where I went wrong. PS I was trying to solve "chef and strings problem" on codechef Relevent code: Scanner cin=new Scanner(System.in); cin.useDelimiter("\n"); String data=cin.next(); System.out.println(data); /* * @param Q no. of chef's requests */ String tempStr=cin.next(); System.out.println(tempStr);; int Q = Integer.parseInt(tempStr); Output: sdfgsdg

I have a method that takes n and returns nth Fibonacci number. Inside the method implementation I use BigDecimal to get the nth Fibonacci number then I use method toBigInteger() to get the number as a BigInteger object and that's surely because I am working with huge numbers in my application. I keep getting correct results until I pass 1475 as an argument for my method. I get NumberFormatException: Infinite or NaN in this case without any clear reason for me. Could you please explain me why am I getting this exception? Here's my method: BigInteger getFib(int n){ double phi = (1 + Math.sqrt(5)

I was writing some code for an interviewstreet.com challenge My code gives a NumberFormatException import java.io.*; public class BlindPassenger { public static void main(String [] args) throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String line = br.readLine(); int t,n; //System.out.println(line); t = Integer.parseInt(line); for(int i=0;i<t;++i) { line = br.readLine(); n = Integer.parseInt(line); --n; if(n == 0) { System.out.println("poor conductor"); } else { char direction='l',seat_posn='l'; int row_no = 0, relative_seat_no = 0; row_no = (int)