nonblocking

问题 I've been reading about non-blocking approaches for some time. Here is a piece of code for so called lock-free counter. public class CasCounter { private SimulatedCAS value; public int getValue() { return value.get(); } public int increment() { int v; do { v = value.get(); } while (v != value.compareAndSwap(v, v + 1)); return v + 1; } } I was just wondering about this loop: do { v = value.get(); } while (v != value.compareAndSwap(v, v + 1)); People say: So it tries again, and again, until all

问题 This question already has answers here : How to read terminal's input buffer immediately after keypress (2 answers) Closed 3 years ago . I have follow situation I have an program make an set of operations on a file continuously and I want, when a specific key is pressed, to stop and do another set of operations. For this I tryed use scanf of an character with fcntl(0, F_SETFL, O_NONBLOCK); and while(feof(stdin)) but it doesn't work as expected. I have searched and in some places someone says

问题 I love the way Go handles I/O multiplexing internally which epoll and another mechanisms and schedules green threads (go-routine here) on its own giving the freedom to write synchronous code. I know TCP sockets are non-blocking and read will give EAGAIN when no data is available. Given that, conn.Read(buffer) will detect this and blocks the go routine doing a connection read with no data available in the socket buffer . Is there a way to stop such go routine without closing the underlying

问题 import tornado.web import Queue QUEUE = Queue.Queue() class HandlerA( tornado.web.RequestHandler ): def get(self): global QUEUE self.finish(QUEUE.get_nowait()) class HandlerB( tornado.web.RequestHandler ): def get(self): global QUEUE QUEUE.put('Hello') self.finish('In queue.') Problem: HandlerA blocks HandlerB for 10 seconds. Browser A handled by HandlerA and waits... Browser B handled by HandlerB and waits.... till timeout exceptions Goal Browser A handled by HandlerA and waits... Browser B

问题 I have created a series of functions that talk to Libcurl Multi and download files asynchronously via ASIO and Boost. Obviously though when I call io_service.run it blocks my main thread when it is run. I have tried to make it non blocking but my app crashes. I was wondering what is the simplest and best approach to running this in the background, in a non-blocking manner and have it call a call-back function when it is done (Like how you can do it in javascript). So I could just go:

问题 I'm trying to understand conceptually why in Play Framework 2.0, it is considered a best practice to call WS.url().get() for web service calls, but if you wrap any other blocking call such as a JDBC call in a promise, you are advised to do it in an execution context other than the default execution context? I understand that, by default, Play Framework's thread pools are configured so that you have one thread per core, and every controller expects to run completely non-blocking code. For this

问题 Running session_write_close() before sleep() in Laravel doesn't seem to be functioning as the session is still blocked from other requests until the current connection is complete. I'm trying to sleep() in Laravel without blocking other requests. Found out that session_write_close() should resolve the problem as mentioned here: Long polling in Laravel (sleep() function make application freeze). But it doesn't work. sleep() is still blocking other requests. The project app is a chat app using

问题 I have to write a small script to deploy a patch for our Application. The patch will replace a couple of files in the application.I decided to depploy the patch using Applescript. The files to be copied are quite large and it takes some time for the files to be copied. I wanted to know if there is any way I can get a dialog box which doesn't block the execution of the script so that I can display some message like Updating.. etc while the patch is applied and then close the dialog box after

问题 I found some articles and even stack| overflow questions addressing this subject, but I still can't do it.. What I want to do is open an instance of firefox from python. then the python application should keep minding its own business and ignore the firefox process. I was able to achive this goal on Windows-7 and XP using: subprocess.Popen() On OS X I tried: subprocess.Popen(['/Applications/Firefox.app/Contents/MacOS/firefox-bin']) subprocess.call(['/Applications/Firefox.app/Contents/MacOS

问题 I understand that they work in some way distinct from making a thread per user. How exactly does that work? (Does 'non-blocking' have something to do with it?) 回答1: From the Twisted documentation: The reactor is the core of the event loop within Twisted -- the loop which drives applications using Twisted. The event loop is a programming construct that waits for and dispatches events or messages in a program. It works by calling some internal or external "event provider", which generally