new-operator

C++ new operator scope

我与影子孤独终老i 提交于 2020-08-26 10:28:46
问题 So I was writing a piece of code where I used new operator to create an object inside a local scope function and returned the reference as a pointer. A* operator+(A that){ int sumA = a + that.getA(); int sumB = b + that.getB(); return new A(sumA, sumB); } In my thought It would not work because the object was created inside the local scope and should be temporary, but it compiled and ran. Can anyone explain to me about this? I am sure there are other things that kinda have the ability of

Create a object in C# without the use of new Keyword? [closed]

妖精的绣舞 提交于 2020-07-05 07:37:09
问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 8 years ago . Is there a way to create a object without the use of new keyword in C# some thing like class.forname(); in java. I want to dynamically create a object of a class. The object creation may depend on the users input

Isn't `delete[]` the counterpart to `new[]`?

拈花ヽ惹草 提交于 2020-06-01 05:33:45
问题 I'm reading to brush up on C++ knowledge that is almost 2 decades old in order to understand online info on the factory pattern. The final usage context will likely be in a different 3rd generation language (3GL), but because of my past experience, I think it's easier to follow C++ than (say) Java, even though the latter may be less intricate in syntax. A bigger reason, however, is that the only code example I can find of the problem being addressed, i.e., in the absence of the factory