Assembly MOV Instruction
问题 Hi guys im working on a CTF challenge and don't quite understand this asm command: mov %edx,0x20(%esp,%eax,4) Im assuming its: move $edx into (0x20 + $esp + $eax + 4) However when I checked this with gdb it isn't correct. Anyone mind explaining how this instruction works? Thanks for your help! 回答1: AT&T syntax for x86 memory references goes like this: displacement(base,index,scale) giving the address of displacement+base+(index*scale). That is, destination memory address for your instuction