nested-lists

jQuery display nested ul on click of div in parent li

半世苍凉 提交于 2019-12-25 02:26:46
问题 I am trying to get a hidden nested ul to display when a div in its parent li is clicked, and am having a heck of a time with it. As is, the initial hiding of the nested ul's works, and the div background image toggles just fine, but nothing else is working. Any suggestions? Current code below: HTML: <div class="browseFields"> <ul id="branches"> <li><div class="buttonShow"></div><a href="#">1</a> <ul class="subField"> <li><a href="#">a</a></li> <li><a href="#">b</a></li> <li><div class=

Get unique values from a nested list in python

孤者浪人 提交于 2019-12-24 21:42:34
问题 I have a nested list (list of list) and I want to remove the duplicates but I'm getting an error. This is an example: images = [ [ { "image_link": "1969.1523.001.aa.cs.jpg", "catalogue_number": "1969.1523", "dataset_name": "marine-transportation-transports-maritimes.xml" }, { "image_link": "1969.1523.001.aa.cs.jpg", "catalogue_number": "1969.1523", "dataset_name": "railway-transportation-transports-ferroviaires.xml" } ], [ { "image_link": "1969.1523.001.aa.cs.jpg", "catalogue_number": "1969

Counting “unique pairs” of numbers into a python dictionary?

早过忘川 提交于 2019-12-24 19:34:13
问题 EDIT: Edited typos; the key values of the dictionary should be dictionaries, not sets. I will keep the typos here though, as the questions below address this question. My apologies for the confusion. Here's the problem: Let's say I have a list of integers whereby are never repeats: list1 = [2, 3] In this case, there is a unique pair 2-3 and 3-2, so the dictionary should be: {2:{3: 1}, 3:{2: 1}} That is, there is 1 pair of 2-3 and 1 pair of 3-2. For larger lists, the pairing is the same, e.g.

Sencha touch nested list no data

瘦欲@ 提交于 2019-12-24 16:14:41
问题 I am new for sencha touch. I using mvc method. Please see my code below Main.js Ext.define('test.view.Main', { extend: 'Ext.tab.Panel', xtype: 'main', requires: [ 'Ext.TitleBar', 'Ext.Video', 'Ext.dataview.NestedList' ], config: { tabBarPosition: 'bottom', items: [ { title: 'Welcome', iconCls: 'home', styleHtmlContent: true, scrollable: true, items: { docked: 'top', xtype: 'titlebar', title: 'Welcome to Sencha Touch 2' }, html: [ "You've just generated a new Sencha Touch 2 project. What you

Nested Lists and List Comprehensions

和自甴很熟 提交于 2019-12-24 11:29:49
问题 I am fairly new to Python and I'm having trouble figuring out how to apply a list comprehension to part of a nested list (specifically at the index level). For instance, if I have the following: my_list = [[1,2], [3,7], [6,9], [4,3]] new_list = [[i*2 for i in sublist] for sublist in my_list] How would I alter my list comprehension to only apply the operation to index 1 of each sublist? I have experimented quite a bit with no success. 回答1: A more general version of mac's: >>> my_list = [[1,2],

Accessing elements in a nested list

牧云@^-^@ 提交于 2019-12-24 10:38:33
问题 I have elements in a nested list called "train_data" like in the example: [0] [0.935897, 1.0, 1.0, 0.928772, 0.053629, 0.0, 39.559883, 0.009494, 0] [1] [0.467681, 1.0, 1.0, 0.778987, 0.069336, 0.0, 56.571999, 0.024675, 0] [2] [0.393258, 1.0, 1.0, 0.843201, 0.068779, 0.0, 66.866669, 0.069206, 1] I would like to access all rows with the first 8 columns (all but the last one), and all rows with only the last column. I need to this without for loops, in a single line of code. I tried something

Extract then row.bind data.frames from nested lists

你。 提交于 2019-12-24 08:29:49
问题 I have a function that outputs a large matrix (Mat1) and a small dataframe (Smalldf1) I store them in a list called "Result". This function is run inside a loop so I create many versions of my "Result" list until my loop ends....each time I add them to a list called "FINAL". At the end of my loop I end up with a List called FINAL, that has many smaller "Result" lists inside...each containing a small dataframe and a large Matrix. I want to rbind all of the small dataframes together to form one

Is there a way of avoiding so many list(chain(*list_of_list))?

本秂侑毒 提交于 2019-12-24 03:52:31
问题 If I have a list of list of list of tuples of two strings. I want to flatten it out to a non-nested list of tuples, I could do this: >>> from itertools import chain >>> lst_of_lst_of_lst_of_tuples = [ [[('ab', 'cd'), ('ef', 'gh')], [('ij', 'kl'), ('mn', 'op')]], [[('qr', 'st'), ('uv', 'w')], [('x', 'y'), ('z', 'foobar')]] ] >>> lllt = lst_of_lst_of_lst_of_tuples >>> list(chain(*list(chain(*lllt)))) [('ab', 'cd'), ('ef', 'gh'), ('ij', 'kl'), ('mn', 'op'), ('qr', 'st'), ('uv', 'w'), ('x', 'y'),

Putting incomplete nested lists in a rectangular ndarray

大憨熊 提交于 2019-12-24 00:27:30
问题 In Python (also using numpy) I have a list of lists of lists, with each list being different lengths. [ [ ["header1","header2"], ["---"], [], ["item1","value1"] ], [ ["header1","header2","header3"], ["item2","value2"], ["item3","value3","value4","value5"] ] ] I want to make this data structure rectangular: i.e. guarantee that len(list[x]) is constant for all x , len(list[x][y]) is constant for all x,y, etc. (This is because I want to import the data structure into numpy) I can think of

Remove items from a nested list based on comparing values obtained from another nested list

亡梦爱人 提交于 2019-12-23 18:50:04
问题 I have two nested lists in the form: a = [[1,2,3,4,5],[3,4,5,6,7,8,9],[5],[1,2,3,6,7,8,9]] b = [[1,4],[6,9]] I want a function that will take these two lists, use the values in each sublist of list b and use that to delete values in list a so that the output looks like this : [[5],[5],[5],[]] i.e. function should iterate all values in list a and remove values such that 1 <= value <= 4 and 6 <= value <= 9 At present I have this : def remove_unnecessary_peaks(peaks_total,peaks_to_be_excluded):