neo4j-apoc

问题 I am trying to create an R-TREE of 5834580 of nodes. I found in this question a similair problem and i tried it's solution, so this is my code : call apoc.periodic.commit("MATCH (pl:pickup_location) WITH collect(pl) AS pickup CALL spatial.addNodes('nyc',pickup) YIELD count RETURN count",{limit:1000}) however, since yesterday the computer didn't finish loading the result. today, i tried the second answer with iterate : CALL apoc.periodic.iterate( "MATCH (pl:pickup_location) RETURN pl", "CALL

问题 I am trying to create an R-TREE of 5834580 of nodes. I found in this question a similair problem and i tried it's solution, so this is my code : call apoc.periodic.commit("MATCH (pl:pickup_location) WITH collect(pl) AS pickup CALL spatial.addNodes('nyc',pickup) YIELD count RETURN count",{limit:1000}) however, since yesterday the computer didn't finish loading the result. today, i tried the second answer with iterate : CALL apoc.periodic.iterate( "MATCH (pl:pickup_location) RETURN pl", "CALL

问题 I am trying to create an R-TREE of 5834580 of nodes. I found in this question a similair problem and i tried it's solution, so this is my code : call apoc.periodic.commit("MATCH (pl:pickup_location) WITH collect(pl) AS pickup CALL spatial.addNodes('nyc',pickup) YIELD count RETURN count",{limit:1000}) however, since yesterday the computer didn't finish loading the result. today, i tried the second answer with iterate : CALL apoc.periodic.iterate( "MATCH (pl:pickup_location) RETURN pl", "CALL

问题 I try to add APOC to my Neo4j instance from Neo4j 3.3.0 docker image but during the startup, I received the following error: neo4j-database> 2017-12-11 19:57:01.189+0000 ERROR [c.g.r.b.RuntimeKernelExtension] Could not start GraphAware Runtime because the database didn't get to a usable state within 5 minutes. neo4j-database> 2017-12-11 19:57:01.192+0000 ERROR Failed to start Neo4j: Starting Neo4j failed: Component 'org.neo4j.server.database.LifecycleManagingDatabase@498f5728' was

问题 When calling a procedure using an evaluated inner query (cypher projection)which would be creating an node or edge a forbidden error is thrown for the admin user. It is possible to run the query outside the procedure. Maybe it is something of an configuration issue? I am trying to run a query using the timetree procedure of GraphAware and the LabelPropagation of Neo4j. But I've been able to get the forbidden error using a much simpler query. I am using Neo4j Desktop. I have tried giving the

问题 CALL apoc.export.csv.query("match (m:Movie) where m.name='Matrix' return m.name","results.csv",{}) Error: Neo.ClientError.Procedure.ProcedureNotFound There is no procedure with the name apoc.export.csv.query registered for this database instance. Please ensure you've spelled the procedure name correctly and that the procedure is properly deployed. Neo4j community version 3.2.6 plugin "apoc-3.2.3.5.jar" is already available in plugins directory. Windows 10 installation 回答1: Make sure that you

问题 CALL apoc.export.csv.query("match (m:Movie) where m.name='Matrix' return m.name","results.csv",{}) Error: Neo.ClientError.Procedure.ProcedureNotFound There is no procedure with the name apoc.export.csv.query registered for this database instance. Please ensure you've spelled the procedure name correctly and that the procedure is properly deployed. Neo4j community version 3.2.6 plugin "apoc-3.2.3.5.jar" is already available in plugins directory. Windows 10 installation 回答1: Make sure that you

问题 This issue is directly related to the previous post: How to calculate rank for float values in Neo4j? I am trying to merge the "rank" and "weight" values with origin and path. I could successfully do this for origin: CALL apoc.load.json("file:///.../input.json") YIELD value UNWIND value.origin AS orig MATCH(origin:concept{name:orig.label}) WITH value, collect(origin) as origins UNWIND value.target AS tar MATCH(target:concept{name:tar.label}) UNWIND origins AS origin WITH origin, target CALL

问题 I have the following graph, describing co-occurrence of car brands in documents: CREATE (`0` :Car {value:"Ford"}) , (`1` :Car {value:"Subaru"}) , (`2` :Car {value:"VW"}) , (`0`)-[:`DOCUMENT` {value:"DOC-1"}]->(`1`) , (`0`)-[:`DOCUMENT` {value:"DOC-2"}]->(`1`) , (`1`)-[:`DOCUMENT` {value:"DOC-3"}]->(`2`); If there are many relationships between two nodes - for the purpose of visualization - I want to replace it with a single one and calculate the weight: VW ---1--- Subaru ---2--- Ford How can

问题 Let's say you have the following 4 nodes: Set 1: (act: "Event Log", timestamp: 3461000) (act: "Uptime Report", timestamp: 3461000) Set 2: (act: "Event Log", timestamp: 149100) (act: "Uptime Report", timestamp: 149100) I am trying to figure out how to map each set of nodes to one node. I tried the following Cypher but all 4 nodes are mapping to only one node, (a) instead of creating two (a) nodes and mapping the 2 sets respectively. Is it necessary to have a condition that looks for the