negative-lookbehind

I'm trying to write a regex that will match everything BUT an apostrophe that has not been escaped. Consider the following: <?php $s = 'Hi everyone, we\'re ready now.'; ?> My goal is to write a regular expression that will essentially match the string portion of that. I'm thinking of something such as /.*'([^']).*/ in order to match a simple string, but I've been trying to figure out how to get a negative lookbehind working on that apostrophe to ensure that it is not preceded by a backslash... Any ideas? - JMT <?php $backslash = '\\'; $pattern = <<< PATTERN #(["'])(?:{$backslash}{$backslash}?+

I have user input where some tags are allowed inside square brackets. I've already wrote the regex pattern to find and validate what's inside the brackets. In user input field opening-bracket could ([) be escaped with backslash, also backslash could be escaped with another backslash (\). I need look-behind sub-pattern to avoid odd number of consecutive backslashes before opening-bracket. At the moment I must deal with something like this: (?<!\\)(?:\\\\)*\[(?<inside brackets>.*?)] It works fine, but problem is that this code still matches possible pairs of consecutive backslashes in front of

Is there a way to do negative and positive lookbehind in VBA regex? I want to not match if the string starts with "A", so I am currently doing ^A at the start of the pattern, then removing the first character of match(0). Obviously not the best method! I am using the regExp object. brettdj VBA offers positive and negative lookaheads but rather inconsistently not lookbehind. The best example of using Regex with VBA that I have seen is this article by Patrick Matthews [Updated example using Execute rather than Replace ] While I am not completely clear on your usage you could use a function like