navigation

问题 Consider following application (it's a schematic preview and it may be a bit tricky to understand!): The app contains 3 screens, which is as follows: Screen 1 : a simple screen which has a simple content (like a web page content without any specific link to another page). Screen 2 : a stacked content which you can navigate through widgets with basic Navigator methods such as pop and push. Screen 3 : a tabbed content, such as bottom navigation bar or tab bar, which has two tabs a and b , which

问题 I need to dynamically present views based on a model so the decision of which view to present and the creation of the views needs to be external to the SwiftUI views. This is working well on iOS 13 but on iOS 14 the first view presents again instead of the second view, although the second view does get initialised as expected the first view is pushed onto the navigation stack a second time. It seems like a iOS 14 bug but perhaps I'm doing something wrong so asking here before filing a bug

问题 Im trying to link a button action in SomeView1() to navigate to a someView2() without having the back button at the top of the screen. Instead, I want to add another button in SomeView2() that will navigate back to SomeView1(). is this possible in SwiftUI yet? SomeView1() struct SomeView1: View { var body: some View { NavigationView { VStack { //...view's content NavigationLink(destination: SomeView2()) { Text("go to SomeView2") } Spacer() } } } } SomeView2() struct SomeView2: View { var body

问题 Im trying to link a button action in SomeView1() to navigate to a someView2() without having the back button at the top of the screen. Instead, I want to add another button in SomeView2() that will navigate back to SomeView1(). is this possible in SwiftUI yet? SomeView1() struct SomeView1: View { var body: some View { NavigationView { VStack { //...view's content NavigationLink(destination: SomeView2()) { Text("go to SomeView2") } Spacer() } } } } SomeView2() struct SomeView2: View { var body

问题 Im trying to link a button action in SomeView1() to navigate to a someView2() without having the back button at the top of the screen. Instead, I want to add another button in SomeView2() that will navigate back to SomeView1(). is this possible in SwiftUI yet? SomeView1() struct SomeView1: View { var body: some View { NavigationView { VStack { //...view's content NavigationLink(destination: SomeView2()) { Text("go to SomeView2") } Spacer() } } } } SomeView2() struct SomeView2: View { var body

问题 Im trying to link a button action in SomeView1() to navigate to a someView2() without having the back button at the top of the screen. Instead, I want to add another button in SomeView2() that will navigate back to SomeView1(). is this possible in SwiftUI yet? SomeView1() struct SomeView1: View { var body: some View { NavigationView { VStack { //...view's content NavigationLink(destination: SomeView2()) { Text("go to SomeView2") } Spacer() } } } } SomeView2() struct SomeView2: View { var body

问题 Im trying to link a button action in SomeView1() to navigate to a someView2() without having the back button at the top of the screen. Instead, I want to add another button in SomeView2() that will navigate back to SomeView1(). is this possible in SwiftUI yet? SomeView1() struct SomeView1: View { var body: some View { NavigationView { VStack { //...view's content NavigationLink(destination: SomeView2()) { Text("go to SomeView2") } Spacer() } } } } SomeView2() struct SomeView2: View { var body

问题 I am currently working on an app which presents a screen modally and another custom progress indicator modally. Is it possible to return to the root View Controller seamlessly? Home -> screen1-> screen2(Custom progressIndicator) I want to dismiss the custom progressIndicator (and the screen presented modally) and return to my home (root) View Controller in one go. self.navigationController?.popToRootViewControllerAnimated(true) Thank you for the help! 回答1: You need to dismiss presented model

问题 I am currently working on an app which presents a screen modally and another custom progress indicator modally. Is it possible to return to the root View Controller seamlessly? Home -> screen1-> screen2(Custom progressIndicator) I want to dismiss the custom progressIndicator (and the screen presented modally) and return to my home (root) View Controller in one go. self.navigationController?.popToRootViewControllerAnimated(true) Thank you for the help! 回答1: You need to dismiss presented model

问题 The drawer has this default three horizontal bars as default icon but i want to change it to something else. I have checked the possible options under the Drawer(), but no property seems to be attached to that. PS: I am a beginner in Flutter. 回答1: This should work. Widget build(BuildContext context) { return Scaffold( appBar: AppBar( title:Text('hi'), leading: IconButton( icon: Icon(Icons.accessible), onPressed: () => Scaffold.of(context).openDrawer(), ), ), ); From the docs -> {Widget