msxsl

xml merge two files using xsl?

由 荒凉一梦 提交于 2019-12-03 18:00:17
问题 I need to merge two similar xml files, but only records which match on common tags, e.g. <type> in the following example: file1.xml is <node> <type>a</type> <name>joe</name> </node> <node> <type>b</type> <name>sam</name> </node> file2.xml is <node> <type>a</type> <name>jill</name> </node> so that I have an output of <node> <type>a</type> <name>jill</name> <name>joe</name> </node> <node> <type>b</type> <name>sam</name> </node> What are the basics of doing this, in xsl? Many thanks. 回答1: This

Using xslt get node value at X position

由 生来就可爱ヽ(ⅴ＜●) 提交于 2019-12-03 17:50:37
问题 How can I get using xslt, node value at X position, without using foreach <items> <item1>x</item1> <item2>x</item2> <item3>x</item3> </items> This is explained in programming sense: <xsl:value-of select="Items/Item[2]"/> ================================================== Just to little expand question, in the following xml: <items> <about>xyz</about> <item1> <title>t1</title> <body>b1</body> </item1> <item2> <title>t2</title> <body>b2</body> </item2> <item3> <title>3</title> <body>3</body> <

Using xslt get node value at X position

由 痞子三分冷 提交于 2019-12-03 07:24:53
How can I get using xslt, node value at X position, without using foreach <items> <item1>x</item1> <item2>x</item2> <item3>x</item3> </items> This is explained in programming sense: <xsl:value-of select="Items/Item[2]"/> ================================================== Just to little expand question, in the following xml: <items> <about>xyz</about> <item1> <title>t1</title> <body>b1</body> </item1> <item2> <title>t2</title> <body>b2</body> </item2> <item3> <title>3</title> <body>3</body> </item3> </items> How can I select second's item title. Answer to expanded question. You can use the

XSL: Avoid exporting namespace definitions to resulting XML documents

由 ≡放荡痞女 提交于 2019-11-27 11:53:58
I'd like to take data from some XML files and transform them into a new XML document. However, I do not want the definition of a namespace in the XSLT to occur in the result document. In other words: source: <Namespace:Root xmlns:Namespace="http://www.something.com"> stylesheet: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:Namespace="http://www.something.com"> result: <resultRoot xmlns:Namespace="http://www.something.com"> <!--I don't want the Namespace definition above--> I am using msxsl for the

XSL: Avoid exporting namespace definitions to resulting XML documents

由 荒凉一梦 提交于 2019-11-27 05:27:31
问题 I'd like to take data from some XML files and transform them into a new XML document. However, I do not want the definition of a namespace in the XSLT to occur in the result document. In other words: source: <Namespace:Root xmlns:Namespace="http://www.something.com"> stylesheet: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:Namespace="http://www.something.com"> result: <resultRoot xmlns:Namespace="http://www
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