milliseconds

问题 i have this code, i need show only hours:min:sec, any help? String var = "1429174464829"; (this is time in System.currentTimeMillis() ) String p = "HH:mm:ss"; SimpleDateFormat f = new SimpleDateFormat(p); long t = var - System.currentTimeMillis(); String result = f.format(new Date(t)); in example String var, is 1 hours higher than System.currentTimeMillis() result problem EDIT: i obtain: result = 21:59:00 thanks 回答1: Java 8 Okay, this is a little unpleasant, but will get the job done, this is

问题 Excuse my ignorance, but I ran into a problem that turned out to be challenging for my current knowledge in programming with Processing, even though the idea is quite simple. You see, I need to add 1 unit to a variable every 10 seconds. This is the code: int i = 0; void setup() { frameRate(60); } void draw() { int time = (millis() % 10000) / 1000; if (time == 9) { i++; } else {} System.out.println("-------------------------------\n" + "Timer: " + time + "\n" + "Adding 1 every 10 seconds: : "

问题 In C# how can I convert Unix-style timestamp to yyyy-MM-ddThh:mm:ssZ? 回答1: Start by converting your milliseconds to a TimeSpan : var time = TimeSpan.FromMilliseconds(milliseconds); Now, in .NET 4 you can call .ToString() with a format string argument. See http://msdn.microsoft.com/en-us/library/system.timespan.tostring.aspx In previous versions of .NET, you'll have to manually construct the formatted string from the TimeSpan's properties. 回答2: new DateTime(numTicks * 10000) The DateTime(long

问题 I'm learing Python and Pygame, and my first thing I'm making is a simple Snake game. I'm trying to make it so that the snake moves once every 0.25 seconds. Here is the part of my code that loops: while True: check_for_quit() clear_screen() draw_snake() draw_food() check_for_direction_change() move_snake() #How do I make it so that this loop runs at normal speed, but move_snake() only executes once every 0.25 seconds? pygame.display.update() I want all of the other function to run normally,

问题 time() is in seconds - is there one in milliseconds? 回答1: The short answer is: $milliseconds = round(microtime(true) * 1000); 回答2: Use microtime. This function returns a string separated by a space. The first part is the fractional part of seconds, the second part is the integral part. Pass in true to get as a number: var_dump(microtime()); // string(21) "0.89115400 1283846202" var_dump(microtime(true)); // float(1283846202.89) Beware of precision loss if you use microtime(true) . There is

问题 I Have a log reading program written in PHP. I want to calculate the time difference of any given two log lines. I found lot of code for calculating the time difference if the two times are give like $time1='10:15:30'; and $time2='10:15:35';. here the time difference will be 5 seconds. But here my input times will be as in the following format $time1='10:15:30:300'; and $time2='11:15:35:450'; I want a function which will receive this times as inputs and give the time difference in

问题 I have a database table, which is filled with data from a mainframe via ETL. One column of that table is called "TOD" as in Time-Of-Day. This columns stores values such as : "CAE7631DC43DC686" "CAE7631C4AC6DC0B" "CAE6216DF2BC0D04" "CAE621D8F9916E8E" all these values are around Feb 10th 2013 and Feb 11th 2013. now, on mainframe, this is a time-date representation (TOD clock). it represents the time past from 01.01.1900 in macroseconds (1/1 000 000 of a second). What I need is a java library /

问题 I am creating a very simple ping program in Python that will send 16- 64 bytes of information to a local server, once the server has received all the bytes, it will send back a 1 Byte message back to the client. (We are testing wifi speeds...) it is very crucial that my client program measures how much time it took to send these bytes. I need a "stopwatch" to measure in milliseconds how much time it took to get the 1 byte message back from the server. My question is, how can I do this? I know

问题 I have a problem changing the current time into milliseconds, the milliseconds shown one month before the set date and time. I know the computer starts the months at 0, how can I solve the problem? First, I transfer the date and the time into String , then I convert the String into date in SimpleDateFormat , and then I convert the date into Long . For example: When the user enter the date "2018/2/14 11:18 "(AM), the date convert to long is "1515899940000" . Here is my code: private void

问题 I have a application which should fire up an alarm at a specified time stored in the database. The time is stored like (HH:mm) format, 24-hour format. Here is the code. SimpleDateFormat sdf = new SimpleDateFormat("HH:mm"); String temp = h+":"+m; Date date = sdf.parse(temp); alarmMgr = (AlarmManager)_c.getSystemService(Context.ALARM_SERVICE); Intent intent = new Intent(_c, AlarmBroadcastReciever.class); alarmIntent = PendingIntent.getBroadcast(_c, requestCode, intent, 0); alarmMgr.set