for-loop

regex for loop over list in python

不问归期 提交于 2021-02-19 02:52:06
问题 I have this list [<th align="left"> <a href="blablabla">F</a>ojweousa</th>, <th align="left"> <a href="blablabla">S</a>awdefrgt</th>, ...] and want the one single character after "> the multiple characters between </a> and </th>, to be concatenated so that i can move on with my life. Here is my code item2 = [] for element in items2: first_letter = re.search('">.</a', str(items2)) second_letter = re.search(r'</a>[a-zA-Z0-9]</th>,', str(items2)) item2.append([str(first_letter) + str(second

Create multiple variables inside for loop

|▌冷眼眸甩不掉的悲伤 提交于 2021-02-19 02:13:18
问题 I am trying to create multiple new variables inside a loop. The number of new variables depends on the lenght of another variable (variable "list" used below). for(var i = 0; i < list.lenght; i++) { var counter + i; // create new variable (i.e. counter1, counter2,...) } I found a lot of very simmilar questions on StackOverflow, and the answer is mostly using an array (i.e. How do I create dynamic variable names inside a loop?). If I use the suggested solution, do I create an array of

Create multiple variables inside for loop

痴心易碎 提交于 2021-02-19 02:12:43
问题 I am trying to create multiple new variables inside a loop. The number of new variables depends on the lenght of another variable (variable "list" used below). for(var i = 0; i < list.lenght; i++) { var counter + i; // create new variable (i.e. counter1, counter2,...) } I found a lot of very simmilar questions on StackOverflow, and the answer is mostly using an array (i.e. How do I create dynamic variable names inside a loop?). If I use the suggested solution, do I create an array of

Create multiple variables inside for loop

那年仲夏 提交于 2021-02-19 02:10:36
问题 I am trying to create multiple new variables inside a loop. The number of new variables depends on the lenght of another variable (variable "list" used below). for(var i = 0; i < list.lenght; i++) { var counter + i; // create new variable (i.e. counter1, counter2,...) } I found a lot of very simmilar questions on StackOverflow, and the answer is mostly using an array (i.e. How do I create dynamic variable names inside a loop?). If I use the suggested solution, do I create an array of

Create multiple variables inside for loop

拈花ヽ惹草 提交于 2021-02-19 02:08:44
问题 I am trying to create multiple new variables inside a loop. The number of new variables depends on the lenght of another variable (variable "list" used below). for(var i = 0; i < list.lenght; i++) { var counter + i; // create new variable (i.e. counter1, counter2,...) } I found a lot of very simmilar questions on StackOverflow, and the answer is mostly using an array (i.e. How do I create dynamic variable names inside a loop?). If I use the suggested solution, do I create an array of

How python handles object instantiation in a ' for' loop

泄露秘密 提交于 2021-02-18 22:36:26
问题 I've got a highly complex class : class C: pass And I've got this test code : for j in range(10): c = C() print c Which gives : <__main__.C instance at 0x7f7336a6cb00> <__main__.C instance at 0x7f7336a6cab8> <__main__.C instance at 0x7f7336a6cb00> <__main__.C instance at 0x7f7336a6cab8> <__main__.C instance at 0x7f7336a6cb00> <__main__.C instance at 0x7f7336a6cab8> <__main__.C instance at 0x7f7336a6cb00> <__main__.C instance at 0x7f7336a6cab8> <__main__.C instance at 0x7f7336a6cb00> <__main__

Linear Regression prediction in R using Leave One out Approach

∥☆過路亽.° 提交于 2021-02-18 19:52:01
问题 I have 3 linear regression models built using the mtcars and would like to use those models to generate predictions for each rows of the mtcars tables. Those predictions should be added as additional columns (3 additional columns) of the mtcars dataframe and should be generated in a for loop using the leave one out approach. Furthermore predictions for model1 and model2 should be performed by "grouping" the cyl numbers whiles predictions made with the model 3 should be accomplished without

Linear Regression prediction in R using Leave One out Approach

寵の児 提交于 2021-02-18 19:51:34
问题 I have 3 linear regression models built using the mtcars and would like to use those models to generate predictions for each rows of the mtcars tables. Those predictions should be added as additional columns (3 additional columns) of the mtcars dataframe and should be generated in a for loop using the leave one out approach. Furthermore predictions for model1 and model2 should be performed by "grouping" the cyl numbers whiles predictions made with the model 3 should be accomplished without

Linear Regression prediction in R using Leave One out Approach

ぃ、小莉子 提交于 2021-02-18 19:51:30
问题 I have 3 linear regression models built using the mtcars and would like to use those models to generate predictions for each rows of the mtcars tables. Those predictions should be added as additional columns (3 additional columns) of the mtcars dataframe and should be generated in a for loop using the leave one out approach. Furthermore predictions for model1 and model2 should be performed by "grouping" the cyl numbers whiles predictions made with the model 3 should be accomplished without

Numpy: how to select items in numpy and assign its value

泄露秘密 提交于 2021-02-17 07:10:12
问题 I have got a problem in assigning new value by list. I want to change 12 items values in s numpy by numpy array's index ,and i hope every index i choose is different. so i made a list random.sample(range(0,len(s),12) to select 12 different index.And through this index change some of values in numpy array s() However, I'm getting the error: SyntaxError: can't assign to function call import numpy as np import random N = 20 s = np.zeros([N]) alist = random.sample(range(0,20),12) alist for i in