longest-substring

来源： https://stackoverflow.com/questions/21930757/longest-repeated-substring

来源： https://stackoverflow.com/questions/21930757/longest-repeated-substring

问题 I searched a lot for a solution and I indeed have found similar questions. This answer gives back the longest sequence of CHARACTERS that might NOT belong in all of the strings in the input list. This answer gives back the longest common sequences of WORDS that MUST belong to all of the strings in the input list. I am looking for a combination of the above solutions. That is, I want the longest sequence of common WORDS that might NOT appear in all of the words/phrases of the input list. Here

问题 I have two vectors that contain the names of towns, both of which are in different formats, and I need to match the names of water districts (water) to their respective census data (towns). Essentially for each row in water, I need to know the best match in towns, since most of them contain similar words such as city. One other problem I see is that words are capitalized in one data set and are not capitalized in another. Here is my example data: towns= c("Acalanes Ridge CDP, Contra Costa

问题 Does anyone know of an R package that solves the longest common substring problem? I am looking for something fast that could work on vectors. 回答1: Check out the "Rlibstree" package on omegahat: http://www.omegahat.org/Rlibstree/. This uses http://www.icir.org/christian/libstree/. 回答2: You should look at the LCS function of qualV package. It is C-implemented, therefore quite efficient. 回答3: The question here is not totally clear on the intended application of the solution to the longest

问题 I am reading about the (apparently) well known problem of the longest common substring in a series of strings, and have been following these two videos which talk about how to solve the problem using suffix arrays: (note that this question doesn't require you to watch them): https://youtu.be/Ic80xQFWevc https://youtu.be/DTLjHSToxmo The first step is that we start by concatenating all the source strings into one big one, separating each with a 'unique' sentinel, where the ASCII code of each

问题 I want to print all the possible solutions to LCS problem. The two strings abcbdab and bdcaba should print following 3 strings: bdab,bcba,bcab. C is the global matrix table which takes values according to algorithm and m, n are the length of the sequences a, b. But The output is something unexpected. #include<stdio.h> #include<conio.h> int co=0,m=0,n=0,c[10][10]; char a[10],b[10]; void main() { int i,j; clrscr(); printf("Enter Two strings: "); scanf("%s",a); scanf("%s",b); m=strlen(a); n

问题 I'm trying to find the number less than 1000 that produces the longest string of repeated numbers when it divides 1. I have a list of decimal numbers and have to find the ones which have the longest repeated sequence. Here's what I have so far numbers = [*2..999] decimal_representations = numbers.map { |number| 1.to_f/number } decimal_representations.map!(&:to_s) I can produce a three dimensional array by using regex. Regex /(.+)\1+/ produces an array of repeated substrings. I want to find

问题 I'm trying to find the Longest Common Substring of two strings using Recursion and DP. Please note that I'm not referring to Longest Contiguous subsequence. So, if the two strings were String s1 = "abcdf"; String s2 = "bzcdf" Longest Common Substring == "cdf" (not "bcdf"). Basically they have to be continuous elements I am trying to do this using recursion and backtracking. However, the problem is that if I use a recursion such as below, the +1 are added upfront in a frame, that is higher up

问题 This question already has answers here : Find longest repeating string based on input in perl (using subroutines) (2 answers) Closed 6 years ago . I was wondering if anyone knows how to simplify, or generalize this code. It gives the correct answer, however it is only applicable to the current situation. My code is as follows: sub longestRepeat{ # list of argument @_ is: (sequence, nucleotide) my $someSequence = shift(@_); # shift off the first argument from the list my $whatBP = shift(@_); #