listdir

Recursive SFTP listdir in Python?

我们两清 提交于 2019-12-01 12:32:53
问题 I need to recursively list the content of a directory that contains a lot of subdirectories (more than 16,000). I am currently using Paramiko's SFTP client, which doesn't offer any recursive listdir functionality. So I have to first run listdir on the parent folder, and then another listdir for each of the (many, many) subdirectories. It takes too long to run. Is there any way to run the recursive listdir in a single SFTP call? I'm not limited to the Paramiko package, it's just the package

Error while using listdir in Python

拜拜、爱过 提交于 2019-11-28 11:10:51
I'm trying to get the list of files in a particular directory and count the number of files in the directory. I always get the following error: WindowsError: [Error 3] The system cannot find the path specified: '/client_side/*.*' My code is: print len([name for name in os.listdir('/client_side/') if os.path.isfile(name)]) I followed the code example given here . I am running the Python script on Pyscripter and the directory /client_side/ do exists. My python code is in the root folder and has a sub-folder called "client_side". Can someone help me out on this? This error occurs when you use os

os.path.isfile() doesn't work. Why?

感情迁移 提交于 2019-11-28 02:16:59
I'm trying to do this: import os [x for x in os.listdir('.') if os.path.isfile(x)] [x for x in os.listdir('dirname') if os.path.isfile(x)] [x for x in os.listdir(os.path.abspath('dirname')) if os.path.isfile(os.path.abspath(x))] The first line works: [x for x in os.listdir('.') if os.path.isfile(x)] But the next two: [x for x in os.listdir('dirname') if os.path.isfile(x)] and [x for x in os.listdir(os.path.abspath('dirname')) if os.path.isfile(os.path.abspath(x))] just output [] Why? Because you need to join the dirname with x , os.listdir() just lists the contents directly, the contents do

Error while using listdir in Python

匆匆过客 提交于 2019-11-26 18:28:39
问题 I'm trying to get the list of files in a particular directory and count the number of files in the directory. I always get the following error: WindowsError: [Error 3] The system cannot find the path specified: '/client_side/*.*' My code is: print len([name for name in os.listdir('/client_side/') if os.path.isfile(name)]) I followed the code example given here. I am running the Python script on Pyscripter and the directory /client_side/ do exists. My python code is in the root folder and has

Non-alphanumeric list order from os.listdir()

不打扰是莪最后的温柔 提交于 2019-11-26 11:19:51
I often use python to process directories of data. Recently, I have noticed that the default order of the lists has changed to something almost nonsensical. For example, if I am in a current directory containing the following subdirectories: run01, run02, ... run19, run20, and then I generate a list from the following command: dir = os.listdir(os.getcwd()) then I usually get a list in this order: dir = ['run01', 'run18', 'run14', 'run13', 'run12', 'run11', 'run08', ... ] and so on. The order used to be alphanumeric. But this new order has remained with me for a while now. What is determining

Non-alphanumeric list order from os.listdir()

笑着哭i 提交于 2019-11-26 01:59:08
问题 I often use python to process directories of data. Recently, I have noticed that the default order of the lists has changed to something almost nonsensical. For example, if I am in a current directory containing the following subdirectories: run01, run02, ... run19, run20, and then I generate a list from the following command: dir = os.listdir(os.getcwd()) then I usually get a list in this order: dir = [\'run01\', \'run18\', \'run14\', \'run13\', \'run12\', \'run11\', \'run08\', ... ] and so