list-manipulation

I have two lists: big_list = [2, 1, 2, 3, 1, 2, 4] sub_list = [1, 2] I want to remove all sub_list occurrences in big_list. result should be [2, 3, 4] For strings you could use this: '2123124'.replace('12', '') But AFAIK this does not work for lists. This is not a duplicate of Removing a sublist from a list since I want to remove all sub-lists from the big-list. In the other question the result should be [5,6,7,1,2,3,4] . Update: For simplicity I took integers in this example. But list items could be arbitrary objects. Update2: if big_list = [1, 2, 1, 2, 1] and sub_list = [1, 2, 1] , I want

I have a list of size < N and I want to pad it up to the size N with a value. Certainly, I can use something like the following, but I feel that there should be something I missed: >>> N = 5 >>> a = [1] >>> map(lambda x, y: y if x is None else x, a, ['']*N) [1, '', '', '', ''] John La Rooy a += [''] * (N - len(a)) or if you don't want to change a in place new_a = a + [''] * (N - len(a)) you can always create a subclass of list and call the method whatever you please class MyList(list): def ljust(self, n, fillvalue=''): return self + [fillvalue] * (n - len(self)) a = MyList(['1']) b = a.ljust(5

This question already has an answer here: How do I concatenate two lists in Python? 25 answers In Python, the only way I can find to concatenate two lists is list.extend , which modifies the first list. Is there any concatenation function that returns its result without modifying its arguments? NPE Yes: list1+list2 . This gives a new list that is the concatenation of list1 and list2 . Depending on how you're going to use it once it's created itertools.chain might be your best bet: >>> import itertools >>> a = [1, 2, 3] >>> b = [4, 5, 6] >>> c = itertools.chain(a, b) This creates a generator