How can I get the concatenation of two lists in Python without modifying either one? [duplicate]

£可爱£侵袭症+ 提交于 2019-11-27 05:50:45
NPE

Yes: list1+list2. This gives a new list that is the concatenation of list1 and list2.

Depending on how you're going to use it once it's created itertools.chain might be your best bet:

>>> import itertools
>>> a = [1, 2, 3]
>>> b = [4, 5, 6]
>>> c = itertools.chain(a, b)

This creates a generator for the items in the combined list, which has the advantage that no new list needs to be created, but you can still use c as though it were the concatenation of the two lists:

>>> for i in c:
...     print i
1
2
3
4
5
6

If your lists are large and efficiency is a concern then this and other methods from the itertools module are very handy to know.

Note that this example uses up the items in c, so you'd need to reinitialise it before you can reuse it. Of course you can just use list(c) to create the full list, but that will create a new list in memory.

Johan Kotlinski

concatenated_list = list_1 + list_2

You can also use sum, if you give it a start argument:

>>> list1, list2, list3 = [1,2,3], ['a','b','c'], [7,8,9]
>>> all_lists = sum([list1, list2, list3], [])
>>> all_lists
[1, 2, 3, 'a', 'b', 'c', 7, 8, 9]

This works in general for anything that has the + operator:

>>> sum([(1,2), (1,), ()], ())
(1, 2, 1)

>>> sum([Counter('123'), Counter('234'), Counter('345')], Counter())
Counter({'1':1, '2':2, '3':3, '4':2, '5':1})

>>> sum([True, True, False], False)
2

With the notable exception of strings:

>>> sum(['123', '345', '567'], '')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: sum() can't sum strings [use ''.join(seq) instead]

you could always create a new list which is a result of adding two lists.

>>> k = [1,2,3] + [4,7,9]
>>> k
[1, 2, 3, 4, 7, 9]

Lists are mutable sequences so I guess it makes sense to modify the original lists by extend or append.

And if you have more than two lists to concatenate:

import operator
list1, list2, list3 = [1,2,3], ['a','b','c'], [7,8,9]
reduce(operator.add, [list1, list2, list3])

# or with an existing list
all_lists = [list1, list2, list3]
reduce(operator.add, all_lists)

It doesn't actually save you any time (intermediate lists are still created) but nice if you have a variable number of lists to flatten, e.g., *args.

Ant

Just to let you know:

When you write list1 + list2, you are calling the __add__ method of list1, which returns a new list. in this way you can also deal with myobject + list1 by adding the __add__ method to your personal class.

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!