lexicographic

问题 The problem statement for this problem can be found at this link - https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=24&page=show_problem&problem=660. When I first read the problem I just could not visualize how suffix array concept is applied in this question. I read the code from this link - https://yuting-zhang.github.io/uva/2016/03/22/UVa-719.html. If some one can take one small example and help me with the complete trace applying Suffix array and LCP concepts

问题 Here it looks like the space after the 3 in both rows breaks the numerical sorting and lets the alphabetic sorting kick in, so that 11 < 2 : $ echo -e '3 2\n3 11' | sort -n 3 11 3 2 In man sort , I read -s, --stable stabilize sort by disabling last-resort comparison which implies that without -s a last-resort comparison is done (between ties, because -s does not affect non-ties). So the question is: how is this last-resort comparison accomplished? A reference to the source code would be

问题 Remove all duplicates from a string and select the lexicographical smallest string possible. For example, the string cbacdcbc would return acdb, not adcb. So this has a relatively simple solution if we don't have to select the string that's lexicographical smallest, but considering that fact, I'm not sure how to come to an efficient solution. Here's what I have so far: string removeDuplicateLetters(string s) { vector<bool> v(26,0); for(int i = 0; i < s.size(); i++) { v[s[i]-'a'] = 1; } string

问题 beginner Java programmer here. I am trying to compare three strings to each other, and have the system spit out the second/middle word in lexicographic order. import java.util.*; public class Ordered2 { public static void main(String[] args) { String firstString, secondString, thirdString; Scanner keyboard = new Scanner(System.in); System.out.println("Enter three different strings."); System.out.println("The string in the middle order lexicographically will be displayed."); firstString =

问题 I have a struct with members x,y,z and w. How do I sort efficiently first by x, then by y, by z and finally by w in C++? 回答1: If you want to implement a lexicographical ordering, then the simplest way is to use std::tie to implement a less-than or greater-than comparison operator or functor, and then use std::sort on a collection of your structs. struct Foo { T x, y, z, w; }; .... #include <tuple> // for std::tie bool operator<(const Foo& lhs, const Foo& rhs) { // assumes there is a bool

问题 I want to generate a lexicographic series of numbers such that for each number the sum of digits is a given constant. It is somewhat similar to 'subset sum problem'. For example if I wish to generate 4-digit numbers with sum = 3 then I have a series like: [3 0 0 0] [2 1 0 0] [2 0 1 0] [2 0 0 1] [1 2 0 0] ... and so on. I was able to do it successfully in Python with the following code: import numpy as np M = 4 # No. of digits N = 3 # Target sum a = np.zeros((1,M), int) b = np.zeros((1,M), int

问题 I want to generate a lexicographic series of numbers such that for each number the sum of digits is a given constant. It is somewhat similar to 'subset sum problem'. For example if I wish to generate 4-digit numbers with sum = 3 then I have a series like: [3 0 0 0] [2 1 0 0] [2 0 1 0] [2 0 0 1] [1 2 0 0] ... and so on. I was able to do it successfully in Python with the following code: import numpy as np M = 4 # No. of digits N = 3 # Target sum a = np.zeros((1,M), int) b = np.zeros((1,M), int

问题 If A has the Ordered[A] trait, I'd like to be able to have code that works like this val collection: List[List[A]] = ... // construct a list of lists of As val sorted = collection sort { _ < _ } and get something where the lists have been sorted in lexicographic order. Of course, just because A has the trait Ordered[A] doesn't mean that List[A] has the trait Ordered[List[A]] . Presumably, however, the 'scala way' to do this is with an implicit def. How do I implicitly convert a List[A] to a

问题 I have the following operator< that is supposed to sort first by a value, then by another value: inline bool operator < (const obj& a, const obj& b) { if(a.field1< b.field1) return true; else return a.field2 < b.field2; } I have the feeling this is incorrect and that you can't do that without another third comparaison test on the members variables, but I can't find any example where this doesn't work. So whould this really sort as expected? thanks edit : I would have coded it as : inline bool

问题 I was curious how std:next_permutation was implemented so I extracted the the gnu libstdc++ 4.7 version and sanitized the identifiers and formatting to produce the following demo... #include <vector> #include <iostream> #include <algorithm> using namespace std; template<typename It> bool next_permutation(It begin, It end) { if (begin == end) return false; It i = begin; ++i; if (i == end) return false; i = end; --i; while (true) { It j = i; --i; if (*i < *j) { It k = end; while (!(*i < *--k))