leap-year

问题 I have a HTML page with 3 dropdowns for the month, day and year and I was wondering if there was a way to populate the month drop down properly depending on the month and year. I haven't done this before on the client side, but it looks like a lot of controls like the jQuery DatePicker are doing that behind the scenes. 回答1: You can play with date objects: var monthStart = new Date(year, month, 1); var monthEnd = new Date(year, month + 1, 1); var monthLength = (monthEnd - monthStart) / (1000 *

问题 We need help for regular expression that work with asp.net asp:RegularExpressionValidator to validate date in MMddyy format. Problem we are facing is leap year. Issue is that is it possible to verify through regular expression that it only accepts valid leap year dates like 02/29/2008 is a valid date but 02/29/2010 is not a valid date. Any regular expression that works with "asp:RegularExpressionValidator"? 回答1: OK, you asked for a regex. Here it is. I think it's immediately obvious why it's

问题 I am using following function to calculate age from given date of birth, but its not showing the correct difference if a leap year day i.e 29 is used. Please help me fix this code. <?php function getAbsAge($birthday) { list($year,$month,$day) = explode("-", $birthday); $year_diff = date("Y") - $year; $month_diff = date("m") - $month; $day_diff = date("d") - $day; if ($day_diff < 0 || $month_diff < 0) { $year_diff--; } if ($year_diff == 0) { $interval = date_diff(date_create(), date_create(

问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: how to find leap year? What will be the exact definition of leap year? AFAIK " A year which is divisible by 4 is a leap year. But for century years' the years which are divisible by 400 is a leap year. " But that definition makes 100, 200, 300, 400.... upto 1700 NOT LEAP years! But in Gregorian calendar all of them are all leap year, check this out. You can also try "call 1700" in Linux to verify. So the correct

问题 The problem is best described in following fiddle : https://jsfiddle.net/bernhard_kern/85s2fm5a/3/. We use two series and two xAxis. xAxis: [{ type: 'datetime', min: new Date('2016/02/22').getTime(), max: new Date('2016/03/05').getTime() }, { type: 'datetime', min: new Date('2015/02/22').getTime(), max: new Date('2015/03/06').getTime() }], I want to compare yearly timseries, which have a different amount of values due to leap year (2016, 29 Feb.). Requirement: Display the equal dates below

问题 I have date when someone is born, and I need to calculate with JavaScript or jQuery or so, how many years, days since birth date, until now. So result can be like 20 years, 89 days. I need to have same results as Wikipedia does with their function of "age in years", as it takes leap years in account and what not. So far I got code that works, but in some cases makes mistake of 1 day. My function is: function DateDiff(date1, date2){ var res=((date1.getTime() - date2.getTime())/1000/60/60/24)

问题 I am writing a program that shows the current years sales from the beginning of the fiscal year to the current date, compared to the same date range of the year before. My question is, what efforts do I need to take for leap year? UPDATE: OK they want it like I said (compare last year up to same date) but if today is non leap year and last year is and today is feb 28th compare to last year up to 29th. Or if today is Feb 29th compare to last year up to 28th. 回答1: Surely that depends on what

问题 I have been tasked to read in some data from some weird old system. The system contains many dates but they are all oddly formatted. They are integer numbers ranging from approximately 55,000 to 80,000 . I know two dates for certain: 58,112 equals February 5, 1960 (originally written as Feb 2,1960 [*]) 61,439 equals March 16, 1969 [*] This typo explains some of the comments initially challenging the leap-year awareness of the calendar. It appears to me that those integer numbers are the

问题 Is there a method in any native Java class to calculate how many days were/will be in a specific year? As in, was it a Leap year (366 days) or a normal year (365 days)? Or do I need to write it myself? I'm calculating the number of days between two dates, for example, how many days left until my birthday. I want to take into account the February 29 of Leap year. I have it all done except that 29th. 回答1: The GregorianCalendar standar class has an isLeapyear() method. If all you've got is a

问题 I am assuming Java has some built-in way to do this. Given a date, how can I determine the date one day prior to that date? For example, suppose I am given 3/1/2009. The previous date is 2/28/2009. If I had been given 3/1/2008, the previous date would have been 2/29/2008. 回答1: Use the Calendar interface. Calendar cal = Calendar.getInstance(); cal.setTime(myDate); cal.add(Calendar.DAY_OF_YEAR,-1); Date oneDayBefore= cal.getTime(); Doing "addition" in this way guarantees you get a valid date.