lcm

Finding the LCM of a range of numbers

由 回眸只為那壹抹淺笑 提交于 2019-11-27 00:45:21
问题 I read an interesting DailyWTF post today, "Out of All The Possible Answers..." and it interested me enough to dig up the original forum post where it was submitted. This got me thinking how I would solve this interesting problem - the original question is posed on Project Euler as: 2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. What is the smallest number that is evenly divisible by all of the numbers from 1 to 20? To reform this as

How to find GCD, LCM on a set of numbers

由 你。 提交于 2019-11-26 14:15:26
What would be the easiest way to calculate Greatest Common Divisor and Least Common Multiple on a set of numbers? What math functions can be used to find this information? Jeffrey Hantin I've used Euclid's algorithm to find the greatest common divisor of two numbers; it can be iterated to obtain the GCD of a larger set of numbers. private static long gcd(long a, long b) { while (b > 0) { long temp = b; b = a % b; // % is remainder a = temp; } return a; } private static long gcd(long[] input) { long result = input[0]; for(int i = 1; i < input.length; i++) result = gcd(result, input[i]); return

How to find GCD, LCM on a set of numbers

由 狂风中的少年 提交于 2019-11-26 03:49:29
问题 What would be the easiest way to calculate Greatest Common Divisor and Least Common Multiple on a set of numbers? What math functions can be used to find this information? 回答1: I've used Euclid's algorithm to find the greatest common divisor of two numbers; it can be iterated to obtain the GCD of a larger set of numbers. private static long gcd(long a, long b) { while (b > 0) { long temp = b; b = a % b; // % is remainder a = temp; } return a; } private static long gcd(long[] input) { long

Least common multiple for 3 or more numbers

由 空扰寡人 提交于 2019-11-26 00:51:59
问题 How do you calculate the least common multiple of multiple numbers? So far I\'ve only been able to calculate it between two numbers. But have no idea how to expand it to calculate 3 or more numbers. So far this is how I did it LCM = num1 * num2 / gcd ( num1 , num2 ) With gcd is the function to calculate the greatest common divisor for the numbers. Using euclidean algorithm But I can\'t figure out how to calculate it for 3 or more numbers. 回答1: You can compute the LCM of more than two numbers
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