lc3

How to increment a letter in string in lc3?

假如想象 提交于 2019-11-28 14:20:32
I am writing an LC3 program that increments each letter of a three-letter word stored in memory following the program. 'a' becomes 'd', 'n' becomes 'q', 'z' becomes 'c', etc. I am using this as LC3 Assembly a reference Here is my code so far .orig x3000 ADD R1, R1, #3 LEA R2, STRING HALT STRING .STRINGZ "anz" .END I was able to figure out how to declare a string of characters in LC3 from my reference. However does anyone how to do the actual incrementation or have any references that I could use to figure out how to do it? Using a while loop, I was able to get it to increment each char of the

How to avoid executing variables in lc3 assembly

廉价感情. 提交于 2019-11-28 11:25:41
问题 I am making my first steps in lc3 assembly programming and I noticed that every time I try to store a negative value in memory, for example using "ST" instruction, there is some kind of error. In this memory location is stored "TRAP xFF" instead... Anybody know how can I get over it?? 回答1: You're getting that error because your variables are apart of the run-time code. It's usually best practice to put your variables at the end of your code after the HALT command. .ORIG x3000 MAIN LD R0, VAR1

Where is -32768 coming from?

点点圈 提交于 2019-11-28 11:25:20
问题 This is LC3 Assembly code I am working with .ORIG x3000 LOOP LDI R0, KBSR BRzp LOOP From LC3 Assembly, I know that LDI is a load indirect addressing mode, meaning it read in an address stored at an location and then read the value at that location From Lc3 Keyboard, I know that KBSR is the keyboard status register, which is one when keyboard has received a new character. Here is my test run in Lc3 simulator? I entered the character 'a' After executing LDI R0, KBSR, register 0 stores a value

How to increment a letter in string in lc3?

寵の児 提交于 2019-11-27 19:36:35
问题 I am writing an LC3 program that increments each letter of a three-letter word stored in memory following the program. 'a' becomes 'd', 'n' becomes 'q', 'z' becomes 'c', etc. I am using this as LC3 Assembly a reference Here is my code so far .orig x3000 ADD R1, R1, #3 LEA R2, STRING HALT STRING .STRINGZ "anz" .END I was able to figure out how to declare a string of characters in LC3 from my reference. However does anyone how to do the actual incrementation or have any references that I could

Why isn't my assembly program setting r1 to the correct value?

北战南征 提交于 2019-11-27 02:17:20
I am writing an assembly program on the LC3 machine. My assembly program is an LC3 program that multiplies R2 and R3 and stores the result in R1. Here is my source code(with comments) ;Sets pc to this address at start of program .ORIG x3000 ;R1 will store the result lets clear it(ANd with 0) AND R1,R1,x0 ;R2 will be multiplied by R3, let's clear both of them AND R2,R2,x0 AND R3,R3,x0 ;Test case 4 * 3 = 12; ADD R2,R2,4 ADD R3,R3,3 ;Add to increment zone LOOP Add R1,R1,R2; ;Decrement the counter, in this case the 3 or R3 ADD R3,R3,x-1 BrP LOOP HALT .END My test case is multiplying 4 * 3. The

Why isn't my assembly program setting r1 to the correct value?

做~自己de王妃 提交于 2019-11-26 12:34:13
问题 I am writing an assembly program on the LC3 machine. My assembly program is an LC3 program that multiplies R2 and R3 and stores the result in R1. Here is my source code(with comments) ;Sets pc to this address at start of program .ORIG x3000 ;R1 will store the result lets clear it(ANd with 0) AND R1,R1,x0 ;R2 will be multiplied by R3, let\'s clear both of them AND R2,R2,x0 AND R3,R3,x0 ;Test case 4 * 3 = 12; ADD R2,R2,4 ADD R3,R3,3 ;Add to increment zone LOOP Add R1,R1,R2; ;Decrement the