json-deserialization

Read specific value from JSON in C#

泪湿孤枕 提交于 2020-12-29 17:01:06
问题 So I have a JSON string where I just want to read a specific value. How do I just pick " Read me please! " from string below? var readString = /*Read me please!*/ JSON string: "{\"aString\":\"Read me please!\"}" For better understanding, how do I do the same here? (just " Read me please! "): "{\"Result\": { \"aString\":\"Read me please!\", \"anotherString\":\"Dont read me!\" } }" If both alternative have different solution I would like to know both. PS: I do not wish to save the value into

Read specific value from JSON in C#

喜夏-厌秋 提交于 2020-12-29 16:59:04
问题 So I have a JSON string where I just want to read a specific value. How do I just pick " Read me please! " from string below? var readString = /*Read me please!*/ JSON string: "{\"aString\":\"Read me please!\"}" For better understanding, how do I do the same here? (just " Read me please! "): "{\"Result\": { \"aString\":\"Read me please!\", \"anotherString\":\"Dont read me!\" } }" If both alternative have different solution I would like to know both. PS: I do not wish to save the value into

Can Swift 4's JSONDecoder be used with Firebase Realtime Database?

徘徊边缘 提交于 2020-12-24 06:49:28
问题 I am trying to decode data from a Firebase DataSnapshot so that it can be decoded using JSONDecoder. I can decode this data fine when I use a URL to access it with a network request (obtaining a Data object). However, I want to use the Firebase API to directly obtain the data, using observeSingleEvent as described on this page. But, when I do this, I cannot seem to convert the result into a Data object, which I need to use JSONDecoder. Is it possible to do the new style of JSON decoding with

Can Swift 4's JSONDecoder be used with Firebase Realtime Database?

£可爱£侵袭症+ 提交于 2020-12-24 06:48:24
问题 I am trying to decode data from a Firebase DataSnapshot so that it can be decoded using JSONDecoder. I can decode this data fine when I use a URL to access it with a network request (obtaining a Data object). However, I want to use the Firebase API to directly obtain the data, using observeSingleEvent as described on this page. But, when I do this, I cannot seem to convert the result into a Data object, which I need to use JSONDecoder. Is it possible to do the new style of JSON decoding with

Can Swift 4's JSONDecoder be used with Firebase Realtime Database?

旧巷老猫 提交于 2020-12-24 06:47:04
问题 I am trying to decode data from a Firebase DataSnapshot so that it can be decoded using JSONDecoder. I can decode this data fine when I use a URL to access it with a network request (obtaining a Data object). However, I want to use the Firebase API to directly obtain the data, using observeSingleEvent as described on this page. But, when I do this, I cannot seem to convert the result into a Data object, which I need to use JSONDecoder. Is it possible to do the new style of JSON decoding with

Gson deserializes with empty fields

二次信任 提交于 2020-11-29 08:54:31
问题 The result variable contains corrected parsed JSON. But after deserialization List contains correct amount of items but all of them are empty. How to fix it? Gson gson = new Gson(); List<UnitView> unitViews = new ArrayList<UnitView>(); // https://stackoverflow.com/questions/5554217/google-gson-deserialize-listclass-object-generic-type Type typeToken = new TypeToken<List<UnitView>>() { }.getType(); unitViews = gson.fromJson(result,typeToken); Even if I do like UnitView[] unitViews = gson

Gson deserializes with empty fields

為{幸葍}努か 提交于 2020-11-29 08:53:41
问题 The result variable contains corrected parsed JSON. But after deserialization List contains correct amount of items but all of them are empty. How to fix it? Gson gson = new Gson(); List<UnitView> unitViews = new ArrayList<UnitView>(); // https://stackoverflow.com/questions/5554217/google-gson-deserialize-listclass-object-generic-type Type typeToken = new TypeToken<List<UnitView>>() { }.getType(); unitViews = gson.fromJson(result,typeToken); Even if I do like UnitView[] unitViews = gson

Gson deserializes with empty fields

余生颓废 提交于 2020-11-29 08:53:06
问题 The result variable contains corrected parsed JSON. But after deserialization List contains correct amount of items but all of them are empty. How to fix it? Gson gson = new Gson(); List<UnitView> unitViews = new ArrayList<UnitView>(); // https://stackoverflow.com/questions/5554217/google-gson-deserialize-listclass-object-generic-type Type typeToken = new TypeToken<List<UnitView>>() { }.getType(); unitViews = gson.fromJson(result,typeToken); Even if I do like UnitView[] unitViews = gson