jshell

I am playing with the JDK9's JShell API. At present, the JShell API automatically launches the remote JVM internally. Instead of starting the process automatically, I want to separate the two process. Note: I understand I can change the VM options. But I want to see if the VM can even be run on a different machine. The default execution control eventually reaches this place in code . If I specify launch, it automatically uses com.sun.jdi.CommandLineLaunch connector, that actually launches the java program by definition. If I specify no-launch, it uses com.sun.jdi.SocketListen as I would expect

I was playing around with JShell after the Java 9 release, and I tried importing a package I made. As the entire application I'm coding it for will be contained in that package, every class but one (which I haven't coded yet) is package-private. My classpath is correct, but I still can't use any of the types declared in the package in JShell (it throws a "cannot find symbol" error). Do I need to make them public for them to be accessible, or is there some way I can test package-private classes ? Here's the exact code I tried. My current directory is C:\Users\Sylvaenn\OneDrive\Documents

When redeclaring Integer 'a' in line 33, why does jshell show the reference variable as an instance of Integer (refer to lines 38 & 39)? After the redeclaration, line 34 shows that 'a' is set to null. When 'a' is declared in line 6 but not given a value, or reset to null in line 22, 'a' is not considered an instance of Integer. I would expect that when the reference variable is redeclared, since its value is null, that it would not be an instance of a type; however, that is not the case. 01: java-lava:~ cafedude$ jshell 02: | Welcome to JShell -- Version 11 03: | For an introduction type:

I was trying out jshell and couldn't find option to paste multiple line expressions. Is it even possible to paste multiple lines in jshell. Similar to what scala offers with paste mode . So if you have code like this: int c = 2; int j = 4; int x = 5; Copy and paste into jshell, only the first two statements are processed. But if you have code like this: int c = 2; int j = 4; int x = 5; And paste into jshell: jshell> int c = 2; int j = 4; int x = 5; c ==> 2 j ==> 4 x ==> 5 Even more lines of code like this: HashMap<Integer, Integer> map2 = new HashMap<>(); for (int i = 0; i < 15; ++i) { map2

Are there any way to execute java command on REPL ( jshell ) as inline command without launching it? E.g. Perl inline command $perl -e 'printf("%06d", 19)' 000019 I have to launch jshell to run any command: $jshell | Welcome to JShell -- Version 9 | For an introduction type: /help intro jshell> String.format("%06d", 19) $1 ==> "000019" I found similar question here , but it's not feasible solution to create a separate jsh file for individual command. Another solution on same post is: echo "1+2"|jshell temp=`echo 'String.format("%06d", 19)'|jshell` echo $temp Ouch output | Welcome to JShell --

I have gone through the introduction to jshell guide and couldn't find description/examples about the -C option in jshell. $jshell --help -C<flag> Pass <flag> to the compiler. Use one -C for each compiler flag or flag argument You can use this option to make use of javac command line arguments for example consider this piece of code: String str = (String)"Hello" Starting jshell normally and using the same would result as: While at the same time you can enable compiler errors on warning( -Werror ) and make use of the -Xlint key cast while compiling to warn you of the explicit cast used in the