jdbctemplate

来源： https://stackoverflow.com/questions/33008205/incorrectresultsetcolumncountexception-incorrect-column-count-expected-1-actu

来源： https://stackoverflow.com/questions/33008205/incorrectresultsetcolumncountexception-incorrect-column-count-expected-1-actu

来源： https://stackoverflow.com/questions/33008205/incorrectresultsetcolumncountexception-incorrect-column-count-expected-1-actu

问题 Why code from "Spring in action 5" don't work (keyHolder.getKey() return null, but entity is saved in DB)? private long savePizzaInfo(Pizza pizza) { pizza.setCreatedAt(new Date()); PreparedStatementCreator psc = new PreparedStatementCreatorFactory( "insert into PIZZA (name, createdAt) values (?, ?)", Types.VARCHAR, Types.TIMESTAMP ).newPreparedStatementCreator( Arrays.asList( pizza.getName(), new Timestamp(pizza.getCreatedAt().getTime()))); KeyHolder keyHolder = new GeneratedKeyHolder();

问题 My question is similar to the one asked here: http://forum.springsource.org/showthread.php?84508-jdbctemplate.query()-sorted-result-set but a clear answer was not provided - an ArrayList does not guarantee order. Basically, I would like to know if the call returned by jdbcTemplate.query() guarantees the order of the resultset and if I can dump it into a LinkedList and pass it along :) Thanks! Edit: I should clarify that the query does include an order by clause, hence my requirements for a

问题 How can I pass multiple parameters in jdbcTemplate queryForInt to get the count. I have tried this, Integer count = this.jdbcTemplate .queryForInt("select count(name) from table_name where parameter1 = ? and parameter2 = ?", new Object[]{parameter1,parameter2}); But its showing queryForInt as strikes. 回答1: Both queryForInt() and queryForLong() are deprecated since version 3.2.2 (correct me if mistake). To fix it, replace the code with queryForObject(String, Class). this.jdbcTemplate

问题 How can I pass multiple parameters in jdbcTemplate queryForInt to get the count. I have tried this, Integer count = this.jdbcTemplate .queryForInt("select count(name) from table_name where parameter1 = ? and parameter2 = ?", new Object[]{parameter1,parameter2}); But its showing queryForInt as strikes. 回答1: Both queryForInt() and queryForLong() are deprecated since version 3.2.2 (correct me if mistake). To fix it, replace the code with queryForObject(String, Class). this.jdbcTemplate

问题 I new in java and try to use spring framework. I have a question. By example, I have table : employee (id_employee, name) employee_product (id_employee_product, id_employee, product_name) if I select an employee data from my Employee table, I can map it in a POJO model User and define the tables structure in that model, like this: public class Employee { private final int id_employee; private final String nama; public Employee(int id_employee, String nama){ this.id_employee = id_employee;

问题 here is my following dao implementaion @Override public List<UserAddress> getAddresses(int pageid,int total) { String sql = "select * FROM user_addresses order by id desc limit "+(pageid-1)+","+total; List<UserAddress> userAddresses = jdbcTemplate.query(sql, new RowMapper<UserAddress>() { @Override public UserSessionLog mapRow(ResultSet rs, int rowNum) throws SQLException { UserAddress userAdd = new UserAddress(); userAdd.setId(rs.getInt("id")); userAdd.setId(rs.getString("city")); return

问题 I am trying to retrieve records from the database by using where clause with few different types of arguments. This is the simple method which I wrote where I am passing breedId and gender as an arguments. public List<Dog> listByBreedIdAndGender(long breedId, String gender) { return query("SELECT * FROM dog_entity WHERE breed__id = ? AND gender = ?", new MapSqlParameterSource(":breedId", breedId) .addValue(":gender", gender)); } private List<Dog> query(String sql, MapSqlParameterSource