jackson

springMvc+swagger整合例子

↘锁芯ラ 提交于 2021-02-02 05:00:18
  Swagger 是一个规范和完整的框架,用于生成、描述、调用和可视化 RESTful 风格的 Web 服务。总体目标是使客户端和文件系统作为服务器以同样的速度来更新。文件的方法,参数和模型紧密集成到服务器端的代码,允许API与接口方法,参数等保存同步,大大减少了接口开发人员的工作量.这个例子是我本地运行正常的,完整demo在文章最后。   第一步:在pom.xml引入相关jar < dependency > < groupId > io.springfox </ groupId > < artifactId > springfox-swagger2 </ artifactId > < version > 2.4.0 </ version > </ dependency > < dependency > < groupId > io.springfox </ groupId > < artifactId > springfox-swagger-ui </ artifactId > < version > 2.4.0 </ version > </ dependency > < dependency > < groupId > com.fasterxml.jackson.core </ groupId > < artifactId > jackson-core </

2021最新 SpringMVC面试题精选(附刷题小程序)

一笑奈何 提交于 2021-01-30 19:13:04
推荐使用小程序阅读 为了能让您更加方便的阅读 本文所有的面试题目均已整理至小程序《 面试手册 》 可以通过微信扫描(或长按)下图的二维码享受更好的阅读体验! [toc] 1. Spring MVC基础 1.1 什么是Spring MVC? Spring MVC是一个基于Java的实现了MVC设计模式的请求驱动类型的轻量级Web框架,通过把模型-视图-控制器分离,将web层进行职责解耦,把复杂的web应用分成逻辑清晰的几部分,简化开发,减少出错,方便组内开发人员之间的配合。 1.2 Spring MVC的优点有那些? 可以支持各种视图技术,而不仅仅局限于JSP; 与Spring框架集成(如IoC容器、AOP等); 清晰的角色分配: 前端控制器(dispatcherServlet) ; 请求到处理器映射(handlerMapping); 处理器适配器(HandlerAdapter); 视图解析器(ViewResolver)。 支持各种请求资源的映射策略。 1.3 Spring MVC的主要组件? DispatcherServlet: 中央控制器,把请求给转发到具体的控制类 Controller: 具体处理请求的控制器 HandlerMapping: 映射处理器,负责映射中央处理器转发给controller时的映射策略 ModelAndView: 服务层返回的数据和视图层的封装类

spring boot(三):Spring Boot中Redis的使用

╄→尐↘猪︶ㄣ 提交于 2021-01-30 08:13:59
https://www.cnblogs.com/ityouknow/p/5748830.html *********************************************************** spring boot对常用的数据库支持外,对nosql 数据库也进行了封装自动化。 redis介绍 Redis是目前业界使用最广泛的内存数据存储。相比memcached,Redis支持更丰富的数据结构,例如hashes, lists, sets等,同时支持数据持久化。除此之外,Redis还提供一些类数据库的特性,比如事务,HA,主从库。可以说Redis兼具了缓存系统和数据库的一些特性,因此有着丰富的应用场景。本文介绍Redis在Spring Boot中两个典型的应用场景。 如何使用 1、引入 spring-boot-starter-redis < dependency > < groupId > org.springframework.boot </ groupId > < artifactId > spring-boot-starter-redis </ artifactId > </ dependency > 2、添加配置文件 # REDIS (RedisProperties) # Redis数据库索引(默认为0) spring.redis.database=0

Unable to deserialise via mixin

天涯浪子 提交于 2021-01-29 21:52:57
问题 Attached is my json. I am receiving this from an endpoint. I have the object type in my consuming app. the object contains; success, message and loggedInMember (which is an object). In the json, the feeClasses contains a lot of fields and objects etc which is why i have not included the whole json. I am only interested in the success and message fields. { "header":{ "messageId":null, "receivedTimestamp":1611246394839, "replyTo":null, "redelivered":false, "originator":null }, "internalId":null

How to ignore field totally by its value when serializing with Jackson with annotation on that field?

半城伤御伤魂 提交于 2021-01-29 20:32:31
问题 Almost the same question but the accepted answer does not fit the general need. Having Simple class and custom serializer like: Example class @Getter @Setter public class ExampleClass { @JsonInclude(JsonInclude.Include.NON_NULL) @JsonSerialize(using = StringSerializer.class) private String stringNull; @JsonInclude(JsonInclude.Include.NON_NULL) @JsonSerialize(using = StringSerializer.class) private String stringOk = "ok"; @JsonInclude(JsonInclude.Include.NON_NULL) @JsonSerialize(converter =

How to ignore field totally by its value when serializing with Jackson with annotation on that field?

那年仲夏 提交于 2021-01-29 17:08:56
问题 Almost the same question but the accepted answer does not fit the general need. Having Simple class and custom serializer like: Example class @Getter @Setter public class ExampleClass { @JsonInclude(JsonInclude.Include.NON_NULL) @JsonSerialize(using = StringSerializer.class) private String stringNull; @JsonInclude(JsonInclude.Include.NON_NULL) @JsonSerialize(using = StringSerializer.class) private String stringOk = "ok"; @JsonInclude(JsonInclude.Include.NON_NULL) @JsonSerialize(converter =

Jackson ObjectMapper in Static Method with Generics

寵の児 提交于 2021-01-29 16:57:21
问题 I have a static method that is intended to read JSON and Parse to a Class (specified at runtime) with ObjectMapper. I would like to return an Object of the 'N' type, but I'm getting an error about using Generics. How can I make the following code accomplish this? public static <N, T extends AbstractRESTApplication> N GET_PAYLOAD( T app, String urlString, REQUEST_TYPE requestType) throws JsonProcessingException, MalformedURLException, IOException, NoSuchAlgorithmException,

After a CustomPrettyPrinter in jackson, Indentation settings are not working

陌路散爱 提交于 2021-01-29 13:50:43
问题 class CustomPrettyPrinter: DefaultPrettyPrinter() { @Throws(IOException::class) override fun writeObjectFieldValueSeparator(jg: JsonGenerator) { jg.writeRaw(": ") } override fun createInstance(): DefaultPrettyPrinter? { return CustomPrettyPrinter() } } fun generateJson() { val file = File("file.json") var jsonData = JSONParser().parse(FileReader(file)) as JSONObject val mapper = ObjectMapper() val indenter : DefaultPrettyPrinter.Indenter = DefaultIndenter(" ", DefaultIndenter.SYS_LF) val

Jackson json property (string) to instance

久未见 提交于 2021-01-29 13:30:33
问题 Assuming I have the following JSON: { "property": "123:1234" } How do I use Jackson annotations to ensure that the string value of "property" is de-serialized to a self-defined class rather than a String object? I went through their documentation and I was unable to find this particular feature. Thanks in advance. 回答1: You could create custom deserializer for your field. Assuming you want to map it to SomeClass object : public class SomeClass { @JsonDeserialize(using =

how to deserialize xml element without tag using jackson

混江龙づ霸主 提交于 2021-01-29 13:17:51
问题 I want deserialize below xml <Test> <message num="90">[WANT TO EXTRACT THIS DATA] <care>test data 1</care> <care>test data 2</care> </message> </Test> Having structure like below @JacksonXmlRootElement(localName = "Test") public class Policy { @JacksonXmlProperty(localName = "message ") private final Message message; //builders } In message class I having like below public class Message{ @JacksonXmlProperty(localName = "care") private final List<String> care; //builders } Now I want to