jackson

Jackson: Is there a way to ignore 0/1 on Boolean deserialization?

由 依然范特西╮ 提交于 2021-02-05 05:52:08
问题 I have a JSON object with a Boolean property that needs to allow only true or false during the deserialization. Any value different of true and false should throw an exception. How can I do that? e.g.: Valid json: { "id":1, "isValid":true } Invalid json: { "id":1, "isValid":1 } Update I tried what @Michał Ziober proposed and it worked fine. As I'm implementing a Spring application (with Webflux) I just had to configure in a different way. I'm posting here what I did: Create a Configuration

jackson xml lists deserialization recognized as duplicate keys

由 こ雲淡風輕ζ 提交于 2021-02-05 02:41:36
问题 I'm trying to convert xml into json using jackson-2.5.1 and jackson-dataformat-xml-2.5.1 The xml structure is received from web server and unknown, therefore I can't have java class to represent the object, and I'm trying to convert directly into TreeNode using ObjectMapper.readTree . My problem is jackson failing to parse lists. It is takes only the last item of the list. code: String xml = "<root><name>john</name><list><item>val1</item>val2<item>val3</item></list></root>"; XmlMapper

Jackson error : no suitable constructor for a simple class

由 做~自己de王妃 提交于 2021-02-04 15:39:32
问题 I am in trouble, here is a class I want to Serialize/Deserialize with Jackson 2.3.2. The serialization works fine but not the deserialization. I have this exception as below: No suitable constructor found for type [simple type, class Series]: can not instantiate from JSON object (need to add/enable type information?) The weirdest thing is that it works perfectly if I comment the constructor! public class Series { private int init; private String key; private String color; public Series(String

Generate JSON sample from Java class

由 只愿长相守 提交于 2021-02-04 15:28:15
问题 How can you generate a JSON sample with dummy data from a Java class definition? (Note: I am not asking about generating JSON from a POJO. This is something that has been asked before on stackoverflow). What I want is to generate some sample dummy data from a Java class directly. For example you have a class like this one: public class Reservation { @ApiModelProperty(value = "") private Traveller leadTraveller = null; @ApiModelProperty(example = "2", value = "") private Integer sourceSystemID

Generate JSON sample from Java class

由 十年热恋 提交于 2021-02-04 15:27:06
问题 How can you generate a JSON sample with dummy data from a Java class definition? (Note: I am not asking about generating JSON from a POJO. This is something that has been asked before on stackoverflow). What I want is to generate some sample dummy data from a Java class directly. For example you have a class like this one: public class Reservation { @ApiModelProperty(value = "") private Traveller leadTraveller = null; @ApiModelProperty(example = "2", value = "") private Integer sourceSystemID

com.fasterxml.jackson.databind.JsonMappingException: Numeric value (1557587751202) out of range of int

由 北慕城南 提交于 2021-02-04 14:08:32
问题 I've generated a Spring Boot web application using Spring Initializr, using embedded Tomcat + Thymeleaf template engine in a macOS Sierra., where I have to parse Json object I have a domain object with this property: @JsonProperty("activationTime") private BigInteger activationTime; But when I parse the object I this error: com.fasterxml.jackson.databind.JsonMappingException: Numeric value (1557587751202) out of range of int at [Source: {"data":[{"id":"18AE62","name":"Device 0018AE62","type":

com.fasterxml.jackson.databind.JsonMappingException: Numeric value (1557587751202) out of range of int

由 北城以北 提交于 2021-02-04 14:08:02
问题 I've generated a Spring Boot web application using Spring Initializr, using embedded Tomcat + Thymeleaf template engine in a macOS Sierra., where I have to parse Json object I have a domain object with this property: @JsonProperty("activationTime") private BigInteger activationTime; But when I parse the object I this error: com.fasterxml.jackson.databind.JsonMappingException: Numeric value (1557587751202) out of range of int at [Source: {"data":[{"id":"18AE62","name":"Device 0018AE62","type":

com.fasterxml.jackson.databind.JsonMappingException: Numeric value (1557587751202) out of range of int

由 好久不见. 提交于 2021-02-04 14:07:43
问题 I've generated a Spring Boot web application using Spring Initializr, using embedded Tomcat + Thymeleaf template engine in a macOS Sierra., where I have to parse Json object I have a domain object with this property: @JsonProperty("activationTime") private BigInteger activationTime; But when I parse the object I this error: com.fasterxml.jackson.databind.JsonMappingException: Numeric value (1557587751202) out of range of int at [Source: {"data":[{"id":"18AE62","name":"Device 0018AE62","type":

How do I configure Jackson Serialization on LocalDateTime and LocalDate for Java?

由 非 Y 不嫁゛ 提交于 2021-02-04 08:14:25
问题 I know that there are many posts on Stackoverflow regarding this topic and I'm sure I've read just about all of them, but I am still struggling to get this working and would appreciate any guidance. This is the Spring Parent and Jackson Dependencies I am using: <parent> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-parent</artifactId> <version>1.5.9.RELEASE</version> </parent> <!-- Jackson --> <dependency> <groupId>com.fasterxml.jackson.module</groupId>

Java 中 POJO 和 json 互转时 忽略隐藏字段

由 拈花ヽ惹草 提交于 2021-02-04 01:57:25
1. 前言 在 Java 开发中有时候某些敏感信息我们需要屏蔽掉，不能被消费这些数据的客户端知道。通常情况下我们会将其设置为 null 或者空字符 "" ，其实还有其它办法，如果你使用了 Jackson 的话。接下来我将以一个实际场景来告诉你可以怎么做。 2. Jackson如何忽略字段 这里都以JSON序列化为例。假如我们在业务中需要返回用户信息，已有的POJO是这样的： import lombok.Data; /** * @java项目www.fhadmin.org */ @Data public class UserInfo { /** * userid */ private String userId; /** * 用户名 */ private String username; /** * 密钥串 */ private String secret; /** * 地址信息 */ private String address; } 业务场景：第三方通过用户的 userId 来获取用户的信息，但是密钥串 secret 显然不能让第三方知道，通常最容易想到的方法是将 secret 字段设置为 null 或者 "" 。如果业务需要批量提供用户信息，即 List<UserInfo> ，我们总不能每次都要遍历一遍吧。 Spring Boot 内置的 Jackson
订阅 jackson