jackson

Serializing an array of arrays in java using Jackson

孤人 提交于 2021-01-29 12:50:46
问题 I'm learning how to use Jackson and I have to serialize an array of ContoCorrente objects public class ContoCorrente { private String proprietario; private ArrayList<MovimentoBancario> movimenti; //methods... } where MovimentoBancario is defined as public class MovimentoBancario { private String data; private String causale; //methods... } I tried with ArrayList<ContoCorrente> conti= new ArrayList<ContoCorrente>(50); for(int i=0; i<50; i++){ //fill array } try { ObjectMapper mapper = new

How do I parse this JSON response into POJO

ε祈祈猫儿з 提交于 2021-01-29 11:03:29
问题 I have the following Test class: import com.fasterxml.jackson.annotation.JsonIgnoreProperties; import com.fasterxml.jackson.core.JsonGenerationException; import com.fasterxml.jackson.databind.DeserializationFeature; import com.fasterxml.jackson.databind.JsonMappingException; import com.fasterxml.jackson.databind.ObjectMapper; import com.ibm.cio.cloud.cost.model.ElasticResponse; import com.jayway.jsonpath.JsonPath; @JsonIgnoreProperties(ignoreUnknown = true) public class TestJSONPaths {

How to display default value in JSON Schema using Jackson

北战南征 提交于 2021-01-29 06:26:18
问题 I am using Jackson to create json schema. I want to display property with their default value in json schema. I tried @JsonProperty annotation with default attribute but still default value is not being display on the json schema. I am using following code to generate Json Schema: ObjectMapper mapper = new ObjectMapper(); JsonSchemaGenerator schemaGen = new JsonSchemaGenerator(mapper); JsonSchema schema = null; try { schema = schemaGen.generateSchema(RootTemplate.class); System.out.println

How to decode generic data in Jackson?

有些话、适合烂在心里 提交于 2021-01-29 05:42:00
问题 How can I do like this: Test<String> data = OBJECT_MAPPER.decodeValue("sss", Test<String>.class); When I call this operation I get an error. I need decode generic class. Thanks for the help. 回答1: You can use TypeReference . Test<String>.class is not possible in Java . TypeReference testStringType = new TypeReference<Test<String>>() { }; Object value = mapper.readValue(json, testStringType); Also works: JavaType javaType = mapper.getTypeFactory().constructParametricType(Test.class, String

How to catch a @JsonFormat exception in spring and handle it gracefully to process the payload?

时间秒杀一切 提交于 2021-01-29 05:18:08
问题 I have a spring app in which I am using the @JsonFormat annotation to deserialize a date format. But when I sent an array of elements my entire payload fails even if one of the entries have an invalid date. Is there a way I can surpass this by gracefully handling this exception, by either replacing the failed date with a default value or ignoring that array entry. jackson.version: 2.7.5 , spring.version: 5.0.0.RELEASE @JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd-MM-yyyy hh:mm:ss

How to get count all json nodes using Jackson framework

爱⌒轻易说出口 提交于 2021-01-29 04:45:26
问题 Here is my user.json { "id":1, "name":{ "first":"Yong", "last":"Mook Kim" }, "contact":[ { "type":"phone/home", "ref":"111-111-1234" }, { "type":"phone/work", "ref":"222-222-2222" } ] }, { "id":2, "name":{ "first":"minu", "last":"Zi Lap" }, "contact":[ { "type":"phone/home", "ref":"333-333-1234" }, { "type":"phone/work", "ref":"444-444-4444" } ] } I would like count how many json object is in there. For example the above json has 2 json object id = 1 and id =2. //tree model approach

Deserialize mutable (primitive/object) JSON property to object with Jackson

自闭症网瘾萝莉.ら 提交于 2021-01-29 04:04:46
问题 Given a JSON object having a mutable property (e.g. label ) which can be either primitive value (e.g. string) or an object. A hypothetical use-case could be a wrapper for pluralized translation of a label: { "label": "User name" } or { "label": { "one": "A label", "other": "The labels" } } The goal is to bring Jackson deserialization always return a fixed structure on the Java-side. Thus, if a primitive value is given it is always translated to a certain property (e.g. other ) of the target

Two way relationship with JsonBackReference & JsonManagedReference

牧云@^-^@ 提交于 2021-01-29 03:39:51
问题 ANSWER I'll solve my problem regarding to this blog Jackson – Bidirectional Relationships Thanks you. UPDATE 2 The problem is about JsonBackReference and JsonManagedReference annotations. With my two way relationship, I have to explicitly select one way for serialization with JsonBackReference and JsonManagedReference. But here, I am in case to use the opposit way " Parent->Child " for a specific requierement (using the way " Child->Parent " by default) When I inversed those two annotations,

Cooperation MongoDB lazy loading with Jackson @JsonIgnore in SpringBoot Rest Controller

删除回忆录丶 提交于 2021-01-29 03:08:29
问题 I have written a RestController in my SpringBoot app. I am using a MongoDB as well. This is my entity: public class LocationEntity { @Id private String id; private String name; @DBRef(lazy = true) @JsonIgnore private UserEntity owner; private String description; @DBRef(lazy = true) private List<RoleEntity> roles; private Date date; public LocationEntity(String name, UserEntity owner, String description, List<RoleEntity> roles, Date date) { this.name = name; this.owner = owner; this

How to convert below JSON to POJO using ObjectMapper of Jackson

有些话、适合烂在心里 提交于 2021-01-29 03:07:13
问题 I am trying below code to convert below JSON to POJO using ObjectMapper class of Jackson but it's throwing exception. Could anyone help me to resolve this issue. Actually JSON is given by UI so can't change format of it. I need to parse this JSON to java object using Jackson library. JSON: data.json { "0": { "location": "6", "userType": "1", "isActive": "1", "userId": "Shailesh@gmail.com" }, "1": { "location": "7", "userType": "2", "isActive": "1", "userId": "Vikram@gmail.com" } } DTOs: