intervals

Generating random numbers on open-open interval (0,1) efficiently

可紊 提交于 2019-12-21 17:00:10
问题 I'm looking for an efficient way to generate random floating-point numbers on the open-open interval (0,1). I currently have an RNG that generates random integers on the closed-closed interval of [0, (2^32)-1]. I've already created a half-open floating point RNG on the interval [0,1) by simply multiplying my result from the integer RNG by 1/((2^32)-1) rather than dividing by (2^32)-1 since it's inefficient. The way I'm currently going about generating numbers on the interval (0,1) is with a

How to spread the average between two intervals in oracle

纵然是瞬间 提交于 2019-12-21 06:01:08
问题 If given the Average for 24 hours for each date in a year. I want to spread this hourly average to average at each minute. e.g. given Date Time Average 01-Jan-15 23:00 20 02-Jan-15 00:00 50 02-Jan-15 01:00 30 I want the output to be calculated something as below .... DateTime AVG_VALUE 01/01/2015 23:00:00 20 01/01/2015 23:01:00 20.5 01/01/2015 23:02:00 21 01/01/2015 23:03:00 21.5 01/01/2015 23:04:00 22 01/01/2015 23:05:00 22.5 01/01/2015 23:06:00 23 01/01/2015 23:07:00 23.5 01/01/2015 23:08

Plotting a number line in Mathematica

吃可爱长大的小学妹 提交于 2019-12-20 19:56:34
问题 I would like to plot a simple interval on the number line in Mathematica. How do I do this? 回答1: Here's another attempt that draws number lines with the more conventional white and black circles, although any graphics element that you want can be easily swapped out. It relies on LogicalExpand[Simplify@Reduce[expr, x]] and Sort to get the expression into something resembling a canonical form that the replacement rules can work on. This is not extensively tested and probably a little fragile.

python: find value within range in float array

心不动则不痛 提交于 2019-12-20 05:38:19
问题 I have the following sorted python list, although multiple values can occur: [0.0943200769115388, 0.17380131294164516, 0.4063245853719435, 0.45796523225774904, 0.5040225609708342, 0.5229351852840304, 0.6145136350368882, 0.6220712583558284, 0.7190096076050408, 0.8486436998476048, 0.8957381707345986, 0.9774325873910711, 0.9832076130275351, 0.985386554764682, 1.0] Now, I want to know the index in the array where a particular value may fall: For example, a value of 0.25 would fall in index 2

Does the angular $interval cancel itself after exceeding 'count' parameter?

一世执手 提交于 2019-12-20 05:23:29
问题 Quick question about the $interval service in angular. Looking at the docs ($interval) they warn you to manually cancel intervals, but you have the option of providing a count parameter upon initialization. Once the timer has "ticked" past the allotted count does it cancel itself or simply stop calling the function and live on in the background? 回答1: TL;DR; After the count, the interval is cleared. As the same documentation says, it is recommended that you cancel the $interval when the scope

JavaScript setInterval immediately run

拟墨画扇 提交于 2019-12-20 04:57:16
问题 I found a solution to run interval in javascript immidiately, not waiting for a first "timeout" setInterval(function hello() { console.log('world'); return hello; }(), 2500); But problem is this solution isn't working is construction like this (function () { window.Banner = { doMagic: function () { setInterval(function magic() { console.log('magic'); return magic; }, 2500); } } })(); Banner.doMagic(); I've tried to return Banner method, to name it and return and no success. Point is what in

Simultaneous calls

大憨熊 提交于 2019-12-19 17:46:18
问题 I'm trying to calculate the number of simultaneous calls at the time a particular call is made by looking at the datetime ranges. My query works, but takes ~10 minutes to perform for only 95,000 records, which is too long. Any ideas for optimization? SELECT r.*, rr.ChannelsActive 'ChannelsActive' FROM #rg r OUTER APPLY ( SELECT SUM(1) AS ChannelsActive FROM #rg r_inner WHERE ( r_inner.CallStart BETWEEN r.CallStart AND r.CallEnd OR r_inner.CallEnd BETWEEN r.CallStart AND r.CallEnd OR r

Create binned variable from results of class interval determination

廉价感情. 提交于 2019-12-19 08:04:32
问题 I want to create a binned variable out of a continuous variable. I want 10 bins, with break points set from whatever results from a jenks classification. How do I assign each value to one of these 10 bins? # dataframe w/ values (AllwdAmt) df <- structure(list(X = c(2078L, 2079L, 2080L, 2084L, 2085L, 2086L, 2087L, 2092L, 2093L, 2094L, 2095L, 4084L, 4085L, 4086L, 4087L, 4088L, 4089L, 4091L, 4092L, 4093L, 4094L, 4095L, 4096L, 4097L, 4098L, 4099L, 4727L, 4728L, 4733L, 4734L, 4739L, 4740L, 4741L,

Create binned variable from results of class interval determination

假如想象 提交于 2019-12-19 08:04:21
问题 I want to create a binned variable out of a continuous variable. I want 10 bins, with break points set from whatever results from a jenks classification. How do I assign each value to one of these 10 bins? # dataframe w/ values (AllwdAmt) df <- structure(list(X = c(2078L, 2079L, 2080L, 2084L, 2085L, 2086L, 2087L, 2092L, 2093L, 2094L, 2095L, 4084L, 4085L, 4086L, 4087L, 4088L, 4089L, 4091L, 4092L, 4093L, 4094L, 4095L, 4096L, 4097L, 4098L, 4099L, 4727L, 4728L, 4733L, 4734L, 4739L, 4740L, 4741L,

Execute a method every x seconds in C

橙三吉。 提交于 2019-12-19 07:53:39
问题 Is there an example of a working timer that executes some function every x amount seconds using C. I'd appreciate an example working code. 回答1: You could spawn a new thread: void *threadproc(void *arg) { while(!done) { sleep(delay_in_seconds); call_function(); } return 0; } ... pthread_t tid; pthread_create(&tid, NULL, &threadproc, NULL); Or, you could set an alarm with alarm(2) or setitimer(2): void on_alarm(int signum) { call_function(); if(!done) alarm(delay_in_seconds); // Reschedule