问题
Is there an example of a working timer that executes some function every x amount seconds using C.
I'd appreciate an example working code.
回答1:
You could spawn a new thread:
void *threadproc(void *arg)
{
while(!done)
{
sleep(delay_in_seconds);
call_function();
}
return 0;
}
...
pthread_t tid;
pthread_create(&tid, NULL, &threadproc, NULL);
Or, you could set an alarm with alarm(2) or setitimer(2):
void on_alarm(int signum)
{
call_function();
if(!done)
alarm(delay_in_seconds); // Reschedule alarm
}
...
// Setup on_alarm as a signal handler for the SIGALRM signal
struct sigaction act;
act.sa_handler = &on_alarm;
act.sa_mask = 0;
act.sa_flags = SA_RESTART; // Restart interrupted system calls
sigaction(SIGALRM, &act, NULL);
alarm(delay_in_seconds); // Setup initial alarm
Of course, both of these methods have the problem that the function you're calling periodically needs to be thread-safe.
The signal method is particularly dangerous because it must also be async-safe, which is very hard to do -- even something as simple as printf
is unsafe because printf
might allocate memory, and if the SIGALRM
interrupted a call to malloc
, you're in trouble because malloc
is not reentrant. So I wouldn't recommend the signal method, unless all you do is set a flag in the signal handler which later gets checked by some other function, which puts you back in the same place as the threaded version.
回答2:
There are various legacy ways to do this using interval timers and signals, but I'm going to present two modern approaches:
Using POSIX timers
The POSIX timer_create
function creates a timer that can be configured to deliver a one-off or periodic notification when the timer expires. When creating the timer, you can request either delivery via a signal or in a new thread. Since using signals correctly is complicated (there are strict rules about what you can and cannot do from a signal handler, and breaking the rules often "seems to work" until you get unlucky), I would recommend using thread-based delivery.
Rolling your own timer with a thread
This is really as easy as it sounds. Make a new thread that goes into a loop sleeping and doing whatever you need done every time the desired time has elapsed.
回答3:
IMO, in this case, you can utilize gettimeofday()
into algorithm like:
use such a while(1)
that counts time difference between current time and last_execution_time, everytime the difference reach 1 seconds, update the last_execution_time and call the function that supposed to run in every 1 second.
#include <stdio.h>
#include <sys/time.h>
#DEFINE DESIRED_INTERVAL 1 //1 second
int get_tv_cur_minus_given(struct timeval *tv, struct timeval *tp_given, int *sign)
{
struct timeval tp_cur;
gettimeofday(&tp_cur,NULL);
tv->tv_sec = tp_cur.tv_sec - tp_given->tv_sec;
tv->tv_usec = tp_cur.tv_usec - tp_given->tv_usec;
if(tv->tv_sec > 0) {
*sign = 1;
if(tv->tv_usec < 0) {
tv->tv_sec--;
tv->tv_usec = 1000000 + tv->tv_usec;
}
}else
if(tv->tv_sec == 0) {
if(tv->tv_usec == 0)
*sign = 0;
else
if(tv->tv_usec < 0) {
*sign = -1;
tv->tv_usec *= -1;
}else
*sign = 1;
}else {
*sign = -1;
if(tv->tv_usec > 0) {
tv->tv_sec++;
tv->tv_usec = 1000000 - tv->tv_usec;
}else
if(tv->tv_usec < 0)
tv->tv_usec *= -1;
return 0;
}
}
int main()
{
struct timeval tv_last_run;
struct timeval tv_diff;
int sign;
while(true)
{
get_tv_cur_minus_given(&tv_diff, &tv_last_run, &sign);
if(tv_diff.tv_sec > DESIRED_INTERVAL)
{
gettimeofday(&tv_last_run,NULL);
printf("\ncall the func here");
}
}
return 0;
}
In case you need different thread out of main thread, move the lines inside main() into a function pointer and pass it through pthread_create function, eg :
void *threadproc(void *arg)
{
while(1)
{
//put the same lines as inside main() function in above code snippet. .
}
}
pthread_create(&tid, NULL, &threadproc, NULL);
来源:https://stackoverflow.com/questions/13923885/execute-a-method-every-x-seconds-in-c