intersection

问题 I've created a Class Mediator in which I want to intersect two policies. I've created the Class Mediator with Carbon Studio for Eclipse, which automatically adds some predefined libs to the build path of my project. One of the libs is neethi-2.0.4.wso2v1.jar. If I want to use the intersect-method I get an exception. If I have a look at the source I see that the intersect-method just throws an "UnsupportedOperationException". So the given neethi lib is useless for intersection, therefore I

问题 I am finding that a lot of time spent in my matlab function is in this code: intersect(freq_bins, our_bins); Both can be rather large vectors, and are comprised of only integers. I just need to know which integers are in both. This is truly the primitive purpose of intersect(), so I suspect that the answer is: it doesn't get any better. But maybe someone has some suggestions. 回答1: intersect calls ismember . In your case, you don't need all the complicated checks that intersect does, so you

问题 Which one of these is faster? Is one "better"? Basically I'll have two sets and I want to eventually get one match from between the two lists. So really I suppose the for loop is more like: for object in set: if object in other_set: return object Like I said - I only need one match, but I'm not sure how intersection() is handled, so I don't know if its any better. Also, if it helps, the other_set is a list near 100,000 components and the set is maybe a few hundred, max few thousand. 回答1: from

问题 I'm trying to find the point of intersection between a sphere and a line but honestly, I don't have any idea of how to do so. Could anyone help me on this one ? 回答1: Express the line as an function of t : { x(t) = x0*(1-t) + t*x1 { y(t) = y0*(1-t) + t*y1 { z(t) = z0*(1-t) + t*z1 When t = 0 , it will be at one end-point (x0,y0,z0) . When t = 1 , it will be at the other end-point (x1,y1,z1) . Write a formula for the distance to the center of the sphere (squared) in t (where (xc,yc,zc) is the

问题 I'm trying to find the point of intersection between a sphere and a line but honestly, I don't have any idea of how to do so. Could anyone help me on this one ? 回答1: Express the line as an function of t : { x(t) = x0*(1-t) + t*x1 { y(t) = y0*(1-t) + t*y1 { z(t) = z0*(1-t) + t*z1 When t = 0 , it will be at one end-point (x0,y0,z0) . When t = 1 , it will be at the other end-point (x1,y1,z1) . Write a formula for the distance to the center of the sphere (squared) in t (where (xc,yc,zc) is the

问题 I have a dataset of ca. 9K lists of variable length (1 to 100K elements). I need to calculate the length of the intersection of all possible 2-list combinations in this dataset. Note that elements in each list are unique so they can be stored as sets in python. What is the most efficient way to perform this in python? Edit I forgot to specify that I need to have the ability to match the intersection values to the corresponding pair of lists. Thanks everybody for the prompt response and

问题 I am using this script from The little schemer, to get intersection of two sets. But I am getting unbound identifier error at 'member?', can anyone please tell what's wrong with it: (define intersect (lambda (set1 set2) (cond ((null? set1) (quote ())) ((member? (car set1) set2) (cons (car setl) (intersect (cdr set1) set2))) (else (intersect (cdr setl) set2))))) I was missing this function above: (define member? (lambda (a lat) (cond ((null? lat) #f) (else (or (eq? (car lat) a) (member? a (cdr

问题 Starting Point I have a multiple array, like the follow example. $array = array ( 'role_1' => array ( 0 => 'value_2', 0 => 'value_3', ), 'role_2' => array ( 0 => 'value_1', 1 => 'value_2', ), 'role_3' => array ( 0 => 'value_2', 1 => 'value_3', ), ) Goal I like to loop about the sub-arrays to get only the intersection. The array was created dynamically, can have a lot of sub-arrays role_[x] and also a lot of key/value inside the sub-arrays. The key is not necessary, only the value. The key is

问题 I want to create different methods for a class called Multiset. I have all the required methods, but I'm unsure of how to write intersection, union, and subset methods. For intersection and union, my code starts like this: def intersect(var) x = Multiset.new end Here is an example: X = [1, 1, 2, 4] Y = [1, 2, 2, 2] then the intersection of X and Y is [1, 2] . 回答1: Utilizing the fact that you can do set operations on arrays by doing & (intersection), - (difference), and | (union). Obviously I

问题 From https://github.com/Microsoft/TypeScript/pull/3622: Supertype collapsing: A & B is equivalent to A if B is a supertype of A. However: type a = string & any; // Resolves to any, not string!? This intersection resolves to any. Isn't 'any' a supertype of string? So shouldn't this intersection be just string, due to supertype collapsing? What am I missing? The use case here is something like: type PropertyMap = { prop1: { name: "somename"; required: any; }; prop2: { name: "someothername";