intersection

Finding the intersection in two lists of tuples regardless of tuple order

混江龙づ霸主 提交于 2021-02-05 07:33:08
问题 I have two lists of tuples listA = [('1','2'),('3','4'),('5','6')] listB = [('2','1'),('7','8')] I want to find the intersection of them even if the order of the tuple in the second list is different. So, for the example above: intersection = [('1','2')] the intersection should return the tuple above though it is not in the same order in listB How can I do that in python the most efficient way? because each of my list has around 2000 tuples. 回答1: >>> set(map(frozenset, listA)) & set(map

Finding the intersection in two lists of tuples regardless of tuple order

余生长醉 提交于 2021-02-05 07:32:45
问题 I have two lists of tuples listA = [('1','2'),('3','4'),('5','6')] listB = [('2','1'),('7','8')] I want to find the intersection of them even if the order of the tuple in the second list is different. So, for the example above: intersection = [('1','2')] the intersection should return the tuple above though it is not in the same order in listB How can I do that in python the most efficient way? because each of my list has around 2000 tuples. 回答1: >>> set(map(frozenset, listA)) & set(map

Pythonic and efficient way to find all the different intersections between two partitions of the same set

元气小坏坏 提交于 2021-01-29 15:20:33
问题 I need to find all the different intersections between two partitions of the same set. For example, if we have the following two partitions of the same set x = [[1, 2], [3, 4, 5], [6, 7, 8, 9, 10]] y = [[1, 3, 6, 7], [2, 4, 5, 8, 9, 10]] the required result is [[1], [2], [3], [4, 5], [6, 7], [8, 9, 10]]. In detail, we calculate the cartesian product between every subset of x and y, and for each of these products, we classify the elements in new subsets accordingly if they belong to the

How to find the intersection point of a ray and a triangle?

北战南征 提交于 2021-01-29 10:00:47
问题 I find the trilinear coordinates of the coordinate of the point of intersection through the barycentric coordinates. Barycentric coordinates are correct (seemingly). private const double Epsilon = 0.000001d; public static Vector3? GetPointIntersectionRayAndTriangle(Vector3 rayOrigin, Vector3 rayDirection, Vector3 vert0, Vector3 vert1, Vector3 vert2) { Vector3 edge1 = new Vector3(); Vector3 edge2 = new Vector3(); Vector3 tvec = new Vector3(); Vector3 pvec = new Vector3(); Vector3 qvec = new

Why does st_intersection return non-polygons?

南笙酒味 提交于 2021-01-29 06:08:52
问题 I have two polygon layers. I want to run st_intersection on them, to give the result of the areas where they overlap as a new layer. The new layer should contain the attributes from both input layers. I found this image which seems to illustrate my desired end results. My two input layers are both polygons: SELECT st_geometrytype(geom), COUNT(*) FROM a GROUP BY st_geometrytype(geom) -- Result is 1368 st_polygons SELECT st_geometrytype(geom), COUNT(*) FROM b GROUP BY st_geometrytype(geom) --

How to find number of self intersection points on 2D plot?

风格不统一 提交于 2021-01-29 05:03:01
问题 I have two numpy arrays x and y : x = [-256.70946838 -188.26946838 -83.86946838 29.81053162 131.89053162 213.67053162 271.09053162 315.17053162 310.53053162 296.03053162 252.53053162 184.67053162 82.59053162 -33.40946838 -139.54946838 -213.78946838 -271.20946838 -317.02946838 -310.64946838 -298.46946838 -256.70946838] y = [ 9.71224758e-02 -3.19097822e-02 -4.80388145e-02 6.48644113e-02 -3.19097822e-02 9.71224758e-02 -1.57807500e-02 6.48644113e-02 -4.02877524e-01 -1.93200105e-01 6.48644113e-02

Using R intersections to create a polygons-inside-a-polygon key using two shapefile layers

不羁岁月 提交于 2021-01-28 08:00:52
问题 The data I have two shapefiles marking the boundaries of national and provincial electoral constituencies in Pakistan. The objective I am attempting to use R to create a key that will generate a list of which provincial-level constituencies are "contained within" or otherwise intersecting with which national-level constituencies, based on their coordinates in this data. For example, NA-01 corresponds with PA-01, PA-02, PA-03; NA-02 corresponds with PA-04 and PA-05, etc. (The key will

Typescript: create union instead intersection when merging optional with required type

被刻印的时光 ゝ 提交于 2020-12-31 05:49:17
问题 When optional and required property are merged via intersection, required wins type A = { who: string } type B = { who?: string } // $ExpectType {who:string} type R = A & B This may lead to runtime errors, when for instance, dealing with default params pattern within a function type Params = { who: string greeting: string } const defaults: Params = { greeting: 'Hello', who: 'Johny 5', } function greeting(params: Partial<Params>){ // $ExpectType Params const merged = {...defaults, ...params}

Typescript: create union instead intersection when merging optional with required type

不打扰是莪最后的温柔 提交于 2020-12-31 05:48:29
问题 When optional and required property are merged via intersection, required wins type A = { who: string } type B = { who?: string } // $ExpectType {who:string} type R = A & B This may lead to runtime errors, when for instance, dealing with default params pattern within a function type Params = { who: string greeting: string } const defaults: Params = { greeting: 'Hello', who: 'Johny 5', } function greeting(params: Partial<Params>){ // $ExpectType Params const merged = {...defaults, ...params}

Typescript: create union instead intersection when merging optional with required type

心不动则不痛 提交于 2020-12-31 05:48:27
问题 When optional and required property are merged via intersection, required wins type A = { who: string } type B = { who?: string } // $ExpectType {who:string} type R = A & B This may lead to runtime errors, when for instance, dealing with default params pattern within a function type Params = { who: string greeting: string } const defaults: Params = { greeting: 'Hello', who: 'Johny 5', } function greeting(params: Partial<Params>){ // $ExpectType Params const merged = {...defaults, ...params}