hotspot

I am trying to make my RPi 3 an AP using Windows 10 IoT core. RPi is connected with internet through Ethernet port and I want to make RPi 3 builtin WiFi to share internet with other devices. I have read documentation page but it is not working for me. I have tried with Windows IoT Onboarding and from PowerShell also. After selecting adapters from IoR Onboarding, clicked on start sharing service and a message appears which says "internet conncetion sharing has started" but I can't find network on other devices. After selecting adapters from IoR Onboarding, clicked on start sharing service and a

Considering the code: someList.forEach(x -> System.out.format("element %s", x)); Theoretically, it should be possible to inline this code and eliminate the indirect function calls by first inlining the forEach method, and then inlining the lambda function body in the inlined forEach code. Is HotSpot capable of performing this optimization? What restrictions govern whether or not it is performed in a particular situation? Your lambda expression is compiled into an ordinary method, while the JRE will generate a class fulfilling the functional interface and calling that method. In current HotSpot

I'm coding on an app where uses can watch a wide array of videos. I open the video in fullscreen on button tap and the user is able to use the playback controls to resize the window. The issue I'm having is that when the user is sharing his internet through hotspot there is a blue bar at the top of the app. When resizing the window at this point will cause a crash in the AVKit framework (I believe). Using Swift 2.3, Xcode 7.3.1. My phone, iPhone 6s, uses iOS 10 and I've also tried it on iOS 9 iPhone 6 Plus, same issue. The crash: Terminating app due to uncaught exception

Are OpenJDK VM and Oracle Hotspot VM still two different JVMs? I can't seem to find any somewhat official documentation on anything about OpenJDK VM. Even in OpenJDK homepage there is an HotSpot Group which develops HotSpot VM. The HotSpot group is comprised of developers involved in the design, implementation, and maintanence of the HotSpot virtual machine However if I check java -version on my Windows machine it prints out Java HotSpot(TM) 64-Bit Server VM But on my Ubuntu VPS OpenJDK 64-Bit Server VM If those are two different VMs what are the main differences between them? Do they have

In my Android application I'm using the following code snippet: @RequiresApi(api = Build.VERSION_CODES.O) private void turnOnHotspot(){ WifiManager manager = (WifiManager) getApplicationContext().getSystemService(Context.WIFI_SERVICE); manager.startLocalOnlyHotspot(new WifiManager.LocalOnlyHotspotCallback(){ @Override public void onStarted(WifiManager.LocalOnlyHotspotReservation reservation) { super.onStarted(reservation); Log.d(TAG, "Wifi Hotspot is on now"); } @Override public void onStopped() { super.onStopped(); Log.d(TAG, "onStopped: "); } @Override public void onFailed(int reason) {

偶尔会看一点点JVM代码,所以尝试构建了一把最新的OpenJDK8 1.环境介绍 1)时间: 2015-05-13 2)系统: Linux haogrgr-vm 3.16.0-30-generic #40~14.04.1-Ubuntu SMP Thu Jan 15 17:43:14 UTC 2015 x86_64 x86_64 x86_64 GNU/Linux 3)Eclipse: Eclipse C/C++ 4.4 4)OpenJDK代码: http://hg.openjdk.java.net/jdk8u/jdk8u40 2.JDK安装 这里安装的是构建OpenJDK需要依赖的JDK, 一般是当前构建版本的上一个版本, 比如我们这里需要安装JDK7. sudo add-apt-repository ppa:webupd8team/java sudo apt-get update sudo apt-get install oracle-java7-installer sudo apt-get install oracle-java7-set-default # 如果你要安装JDK8: # sudo apt-get install oracle-java8-installer # sudo apt-get install oracle-java8-set-default #

第一章：介绍和概述 Java HotSpot虚拟机是Sun公司的Java平台一个高效的虚拟机实现。Java HotSpot技术提供Java标准平台的基础设施，提供对快速开发、部署关键业务的桌面和企业应用程序的解决方案。Java SE可应用在Solaris操作环境、Linux和Windows下，也可以应用在其它通过Java技术认证的平台下。 Java平台已经成为软件开发和部署的主流工具。拥有成千上万的开发者和用户，java平台在如下许多方面增长迅速：从信用卡到无线设备，从桌面机到大型机。Java平台是部署网页Applet、Web服务、大型商业程序等应用的基础设施。 Java HotSpot构建在Java技术跨平台和健壮的安全模型之上，并具备可扩展性、质量和性能方面的新特性。除了这些新特性之外，该版本的HotSpot是向上兼容的。 Java HotSpot几乎全面支持企业应用的开发、部署和管理，它被用在： 集成开发环境(IDE)，如Sun Java Studio工具、NetBeans开源项目、IBM的Eclipse，Oracle JDeveloper等等。 应用服务提供者，如Sun Java系统应用服务器、BEA系统WebLogic软件、IBM WebSphere软件，Apple电脑的WebObjects软件等等。 Sun Microsystems, Inc

What is the API call I need to make in Android 2.2 (Froyo) to create a Wifi hotspot (as seen in the Tethering and Portable Hotspot settings item). markov00 You can call private boolean setWifiApEnabled(WifiConfiguration wifiConfig, boolean enabled); using reflection :) after getting the WifiManager use the reflection to get the WifiManager declared methods, look for this method name setWifiApEnabled and invoke it through the WifiManager object These API are marked as @hide, so currently you cannot use them directly, but they appear on the AIDL for the WifiManager so their are accessible! An