hiveql

问题 I need to retrieve the columns from a hive table that must begin with uppercase letter and end with digit. I used this query select * from tab1 where col1 like '[A-Z]%[0-9]'; But not able to retrieve the records ,getting only empty result. 回答1: rlike / regexp select * from tab1 where col1 rlike '^[A-Z].*[0-9]$'; 来源： https://stackoverflow.com/questions/42809183/using-like-operator-to-check-for-pattern-in-hive

问题 I need to retrieve the columns from a hive table that must begin with uppercase letter and end with digit. I used this query select * from tab1 where col1 like '[A-Z]%[0-9]'; But not able to retrieve the records ,getting only empty result. 回答1: rlike / regexp select * from tab1 where col1 rlike '^[A-Z].*[0-9]$'; 来源： https://stackoverflow.com/questions/42809183/using-like-operator-to-check-for-pattern-in-hive

问题 I am trying to delete a part of a string in HIVE. I want to delete the last eleven characters for all records in a column. The data looks like: 1018492743|0001-01-01 I want it to look like: 1018492743 The code I have tried looks like: Select right(a.ord_id, len(a.ord_id)-ll) It isn't working because len isnt a function in HIVE Another issue I have is that some of the records are already in the correct format. Does this mean I need to create a case statement that checks for this? 回答1: You can

问题 I am trying to delete a part of a string in HIVE. I want to delete the last eleven characters for all records in a column. The data looks like: 1018492743|0001-01-01 I want it to look like: 1018492743 The code I have tried looks like: Select right(a.ord_id, len(a.ord_id)-ll) It isn't working because len isnt a function in HIVE Another issue I have is that some of the records are already in the correct format. Does this mean I need to create a case statement that checks for this? 回答1: You can

问题 I am trying to delete a part of a string in HIVE. I want to delete the last eleven characters for all records in a column. The data looks like: 1018492743|0001-01-01 I want it to look like: 1018492743 The code I have tried looks like: Select right(a.ord_id, len(a.ord_id)-ll) It isn't working because len isnt a function in HIVE Another issue I have is that some of the records are already in the correct format. Does this mean I need to create a case statement that checks for this? 回答1: You can

问题 I have a table: key product_code cost 1 UK 20 1 US 10 1 EU 5 2 UK 3 2 EU 6 I would like to find the sum of all products for each group of "key" and append to each row. For example for key = 1, find the sum of costs of all products (20+10+5=35) and then append result to all rows which correspond to the key = 1. So end result: key product_code cost total_costs 1 UK 20 35 1 US 10 35 1 EU 5 35 2 UK 3 9 2 EU 6 9 I would prefer to do this without using a sub-join as this would be inefficient. My

问题 I have a requirement to insert streaming of records into Hive partitioned table. The table structure is something like CREATE TABLE store_transation ( item_name string, item_count int, bill_number int, ) PARTITIONED BY ( yyyy_mm_dd string ); I would like to understand how Hive handles inserts in the internal table. Does all record insert into a single file inside the yyyy_mm_dd=2018_08_31 directory? Or hive splits into multiple files inside a partition, if so when? Which one performs well

问题 I have a requirement to insert streaming of records into Hive partitioned table. The table structure is something like CREATE TABLE store_transation ( item_name string, item_count int, bill_number int, ) PARTITIONED BY ( yyyy_mm_dd string ); I would like to understand how Hive handles inserts in the internal table. Does all record insert into a single file inside the yyyy_mm_dd=2018_08_31 directory? Or hive splits into multiple files inside a partition, if so when? Which one performs well

问题 I have a requirement to insert streaming of records into Hive partitioned table. The table structure is something like CREATE TABLE store_transation ( item_name string, item_count int, bill_number int, ) PARTITIONED BY ( yyyy_mm_dd string ); I would like to understand how Hive handles inserts in the internal table. Does all record insert into a single file inside the yyyy_mm_dd=2018_08_31 directory? Or hive splits into multiple files inside a partition, if so when? Which one performs well

来源： https://stackoverflow.com/questions/52091433/hive-alter-table-change-column-name-gives-null-to-the-renamed-column