graph

Create a boxplot for multiple stations and line joining median of the stations

久未见 提交于 2021-02-08 07:29:34
问题 I have a dataset as follows: 24 i=6,j=529, Depth Avg 129 1 129.041687011719 1.00000035762787 129.08332824707 .99999988079071 129.125015258789 1.00000011920929 129.166687011719 1.00000023841858 129.20832824707 1.00000035762787 129.250030517578 1.00000047683716 129.29167175293 1.00000035762787 129.333343505859 1.00000011920929 129.375030517578 .999998927116394 129.41667175293 .999999940395355 129.458358764648 1.00000107288361 129.5 1.00000059604645 129.541687011719 1.00000059604645 129

mxGraph: Which event is fired when I move a handle point of an edge?

时光毁灭记忆、已成空白 提交于 2021-02-08 06:57:21
问题 I move the point and I want to save the position after the movement. How can I catch this event? I know, the edge gets the points after moving, I can find control points in the geometry. But I need the moment of the end of movement. 回答1: I'm not sure if it helps, but I usually have a listener to mxEvent.CHANGE, and process each change... Something like this: model.addListener(mxEvent.CHANGE, function(sender, evt) { var changes = evt.getProperty('edit').changes; for (var i = 0; i < changes

How to check if circles overlap

本小妞迷上赌 提交于 2021-02-08 05:41:46
问题 I'm trying to write a program that checks if a circle contains another circle, if a certain point is inside a circle, or the one I'm having trouble with, if a circle overlaps with another circle. import javafx.scene.shape.Circle; public class Problem10_11 { public static void main(String[] args) { //Create circle with certain parameters. Circle2D c1 = new Circle2D(2, 2, 5.5); //Create output which will be tested by all our methods. System.out.println("The area for circle 1 is " +c1.getArea()+

How to check if circles overlap

我的未来我决定 提交于 2021-02-08 05:41:37
问题 I'm trying to write a program that checks if a circle contains another circle, if a certain point is inside a circle, or the one I'm having trouble with, if a circle overlaps with another circle. import javafx.scene.shape.Circle; public class Problem10_11 { public static void main(String[] args) { //Create circle with certain parameters. Circle2D c1 = new Circle2D(2, 2, 5.5); //Create output which will be tested by all our methods. System.out.println("The area for circle 1 is " +c1.getArea()+

A BFS Algorithm for Weighted Graphs - To Find Shortest Distance

社会主义新天地 提交于 2021-02-08 04:56:07
问题 I've seen quite a few posts (viz. post1, post2, post3) on this topic but none of the posts provides an algorithm to back up respective queries. Consequently I'm not sure to accept the answers to those posts. Here I present a BFS based shortest-path (single source) algorithm that works for non-negative weighted graph. Can anyone help me understand why BFS (in light of below BFS based algorithm) are not used for such problems (involving weighted graph)! The Algorithm: SingleSourceShortestPath

A BFS Algorithm for Weighted Graphs - To Find Shortest Distance

别说谁变了你拦得住时间么 提交于 2021-02-08 04:55:28
问题 I've seen quite a few posts (viz. post1, post2, post3) on this topic but none of the posts provides an algorithm to back up respective queries. Consequently I'm not sure to accept the answers to those posts. Here I present a BFS based shortest-path (single source) algorithm that works for non-negative weighted graph. Can anyone help me understand why BFS (in light of below BFS based algorithm) are not used for such problems (involving weighted graph)! The Algorithm: SingleSourceShortestPath

Visualizing time series data of graph nodes in plotly

北城余情 提交于 2021-02-08 04:38:23
问题 I've a graph created in Networkx and plotted using plotly Code: import numpy as np import pandas as pd import networkx as nx import matplotlib.pyplot as plt import plotly.graph_objects as go from pprint import pprint from collections import OrderedDict def get_edge_trace(G): edge_x = [] edge_y = [] for edge in G.edges(): x0, y0 = G.nodes[edge[0]]['pos'] x1, y1 = G.nodes[edge[1]]['pos'] edge_x.append(x0) edge_x.append(x1) edge_x.append(None) edge_y.append(y0) edge_y.append(y1) edge_y.append

Set a colormap under a graph

不羁岁月 提交于 2021-02-08 04:22:11
问题 I know this is well documented, but I'm struggling to implement this in my code. I would like to shade the area under my graph with a colormap. Is it possible to have a colour, i.e. red from any points over 30, and a gradient up until that point? I am using the method fill_between, but I'm happy to change this if there is a better way to do it. def plot(sd_values): plt.figure() sd_values=np.array(sd_values) x=np.arange(len(sd_values)) plt.plot(x,sd_values, linewidth=1) plt.fill_between(x,sd

R visNetwork: Multiple graph layout?

邮差的信 提交于 2021-02-07 20:21:05
问题 I would like to position two visNetwork plots side-by-side for visual comparison. Multi-plot positioning is possible using igraph with par() or layout(). Is there a way to do this for visNetwork? Work-arounds/kludges (including RShiny, etc.) are acceptable answers - whatever works to provide a side-by-side visNetwork display. Note that ID numbers etc. overlap, so putting both networks into the same graph would be a lot of data manipulation that I wish to avoid. Here is an example of the type

R visNetwork: Multiple graph layout?

☆樱花仙子☆ 提交于 2021-02-07 20:20:29
问题 I would like to position two visNetwork plots side-by-side for visual comparison. Multi-plot positioning is possible using igraph with par() or layout(). Is there a way to do this for visNetwork? Work-arounds/kludges (including RShiny, etc.) are acceptable answers - whatever works to provide a side-by-side visNetwork display. Note that ID numbers etc. overlap, so putting both networks into the same graph would be a lot of data manipulation that I wish to avoid. Here is an example of the type