getline

The usage of pipe in AWK

假装没事ソ 提交于 2019-12-03 16:31:49
What I want is to get the reversed string of current line, I tried to use the rev command in the AWK but cannot get the current result. $ cat myfile.txt abcde $ cat myfile.txt | awk '{cmd="echo "$0"|rev"; cmd | getline result; print "result="$result; close(cmd);}' abcde I want to get edcba in the output. I know there are some other ways to get the reversed string like $ cat myfile.txt | exec 'rev' . Using AWK here is because there are some other processes to do. Did I miss anything? The system function allows the user to execute operating system commands and then return to the awk program. The

c getline skip blank line

匿名 (未验证) 提交于 2019-12-03 10:03:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: while(getline (&line, &line_size, f) != -1){} I'm using this function to read line line. But i want to know when i'm reading a blank line. Can someone help? 回答1: so as H2CO3 already mentioned you can use the line length for this: while (getline (&line, &line_size, f) != -1) { if (strlen(line) == 1) { printf("H2CO3 spotted a blank line\n"); } /* or alternatively */ if ('\n' == line[0]) { printf("Ed Heal also spotted the blank line\n"); } .. } 回答2: You need to define blank line. Also, because "The getline function reads an entire line from a

How to use the getline command in c++?

别来无恙 提交于 2019-12-03 09:59:21
问题 I'm trying to turn a cout command into a getline command in c++. This is my code that I'm trying to changes.... for (int count=0; count < numberOfEmployees; count++) { cout << "Name: "; cin >> employees[count].name; cout << "Title: "; cin >> employees[count].title; cout << "SSNum: "; cin >> employees[count].SSNum; cout << "Salary: "; cin >> employees[count].Salary; cout << "Withholding Exemptions: "; cin >> employees[count].Withholding_Exemptions; } I'm trying to change this line: cin >>

getline(cin.name) gets skipped

匿名 (未验证) 提交于 2019-12-03 08:52:47
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I call a function from a function in C++ that has the line getline(cin,name) where name is a string. the first time through the loop, the program does not wait for input. It will on all other passes through the loop. Any ideas on why? void getName (string& name) { int nameLen; do{ cout << "Enter the last Name of the resident." << endl << endl << "There should not be any spaces and no more than 15" << " characters in the name." << endl; getline(cin,name); cout << endl; nameLen = name.length();// set len to number of characters input cout <<

getline over a socket

匿名 (未验证) 提交于 2019-12-03 08:48:34
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: Is there a libc function that would do the same thing as getline, but would work with a connected socket instead of a FILE * stream ? A workaround would be to call fdopen on a socket. What are things that should be taken care of, when doing so. What are reasons to do it/ not do it. One obvious reason to do it is to call getline and co, but maybe it is a better idea to rewrite some custom getline ? 回答1: when you call a read on a socket, then it can return a zero value prematurely. eg. read ( fd , buf , bufsize ) can return a value

Why doesn&#039;t std::getline block?

匿名 (未验证) 提交于 2019-12-03 08:48:34
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have this code in an Objective-C class (in an Objective-C++ file): +(NSString *)readString { string res; std::getline(cin, res); return [NSString stringWithCString:res.c_str() encoding:NSASCIIStringEncoding]; } When I run it, I get a zero-length string, Every time. Never given the chance to type at the command line. Nothing. When I copy this code verbatim into main() , it works. I have ARC on under Build Settings. I have no clue what it going on. OSX 10.7.4, Xcode 4.3.2. It is a console application. 回答1: It means there is input waiting to

std::cin skips white spaces

匿名 (未验证) 提交于 2019-12-03 08:28:06
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: So I am trying to write a function to check whether a word is in a sentence, by looping through a char array and checking for the same string of char's. The program works as long as the Sentence doesn't have any spaces. I googled around and they are all the same suggestions; cin.getline But however I implement it, it either doesn't run or skips the entire input and goes straight towards the output. How can I account for spaces? #include <iostream> using namespace std; bool isPartOf(char *, char *); int main() { char* Word= new char[40]; char

Can I combine all the sections “Objdump -S -d elf-file” generate into a re-assemble capable file?

匿名 (未验证) 提交于 2019-12-03 08:28:06
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: THe elf file is static linked and currently the objdump's output is something like: Disassembly of section: .init: xxxxxx Disassembly of section: .plt: xxxxxx Disassembly of section: .text: xxxxxx basically what I want to achieve is "elf-file -(disassemble by objdump)-> assemble file --(re-compile)--> same functionality " I don't need the re-compiled binary has the binary content same as the original one, only same functionality is enough. After a quick search, basically the answer is no , and they argued that disassemble file lost some

日常笔记4关于cin、cin.get()、cin.getline()、getline()使用区别

时光怂恿深爱的人放手 提交于 2019-12-03 07:00:01
1.关于PAT中段错误 使用字符数组出现错误: char str[256]; 报错段错误,然后改用C++中的string 改成: string str; 同char数组一样,也可以使用下标来取单个字符 但是还有区别就是,判断字符长度 char str[256],使用int len = strlen(str); string str,使用int len = str.length(); 2.关于输出输出cin、cin.get()、cin.getline()、getline()使用 前言 在做PATB1033 旧键盘打字(20分)时,有一个答案错误一直没有解决 只拿了19分,百思不得其解 然后我把cin >> str;换成getline(cin, str);问题解决 cin.getline()和getline()是两回事。 cin.getline()是在#include 而getline(cin,str)用法:接收一个字符串,可以接收空格并输出,需包含“#include ” 1. cin 结束条件:[enter],[space],[tab] 处理方法:cin遇到缓冲区中的[enter],[space],[tab]会结束当前输入, 并舍弃[enter],[space],[tab],继续下一项输入, 当有连续[space],[enter,[tab]会全部舍弃。 2. cin.get()

Haskell Input Return Tuple

匿名 (未验证) 提交于 2019-12-03 03:03:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: i wonder can a IO() function return tuple because i would like to get these out of this function as input for another function. investinput :: IO()->([Char], Int) investinput = do putStrLn "Enter Username : " username <- getLine putStrLn "Enter Invest Amount : " tempamount <- getLine let amount = show tempamount return (username, amount) Please help. Thanks. 回答1: IO in Haskell doesn't work like IO in the languages you're used to. All functions in Haskell must be pure: that is, if a function f is called with the argument x getLine should have