function-binding

How does Function.bind.bind(Function.call) uncurry?

杀马特。学长 韩版系。学妹 提交于 2019-11-28 06:33:12
We have this line in my code base: var uncurryThis = Function.bind.bind(Function.call); That I'm trying to work through. Presumably, it uncurries. How do I work this out? I guess it's a version of Function.bind whose own this is bound to Function.call . Doesn't help me enough. And I haven't found any uses, so I'm not even sure if you call it standalone or need to call it "as a method", only, you know, bind it first. It passes the call function to the bind function, with the bind function itself being the value of this . Thus you get in return a wrapper around the bind function that arranges

How does Function.bind.bind(Function.call) uncurry?

蓝咒 提交于 2019-11-27 01:23:54
问题 We have this line in my code base: var uncurryThis = Function.bind.bind(Function.call); That I'm trying to work through. Presumably, it uncurries. How do I work this out? I guess it's a version of Function.bind whose own this is bound to Function.call . Doesn't help me enough. And I haven't found any uses, so I'm not even sure if you call it standalone or need to call it "as a method", only, you know, bind it first. 回答1: It passes the call function to the bind function, with the bind function

Explain bindbind() function

孤人 提交于 2019-11-26 16:29:53
问题 Can someone explain this function? var bindbind = Function.prototype.bind.bind(Function.prototype.bind); I understand the result it produce: var bindedContextFunc = bindbind(function)(context); bindedContextFunc(args); But do not understand process of creating this functions, I mean part bind(Function.prototype.bind) 回答1: OK. We have three times the Function.prototype.bind function here, whose (simplified) code function bind(context) { var fn = this; return function() { return fn.apply

What are the differences (if any) between ES6 arrow functions and functions bound with Function.prototype.bind?

有些话、适合烂在心里 提交于 2019-11-26 01:47:45
问题 It seems to me that, in ES6, the following two functions are very nearly identical: function () { return this; }.bind(this); () => { return this; }; The end result seems the same: arrow functions produce a JavaScript function object with their this context bound to the same value as the this where they are created. Obviously, in the general sense, Function.prototype.bind is more flexible than arrow functions: it can bind to values other than the local this , and it can bind any function\'s

What are the differences (if any) between ES6 arrow functions and functions bound with Function.prototype.bind?

南笙酒味 提交于 2019-11-25 22:03:19
It seems to me that, in ES6, the following two functions are very nearly identical: function () { return this; }.bind(this); () => { return this; }; The end result seems the same: arrow functions produce a JavaScript function object with their this context bound to the same value as the this where they are created. Obviously, in the general sense, Function.prototype.bind is more flexible than arrow functions: it can bind to values other than the local this , and it can bind any function's this at any point in time, potentially long after it is initially created. However, I'm not asking how