formset

Model Formset - By Default model formset is rendering one extra field (2 fields in total)

Deadly 提交于 2019-12-04 10:17:52
My model formset without even defining "extra" parameters in modelformset_factory is rendering one extra field in the template. I have tried many variations but it didn't work. If I print the form (the model form) on the command line it just prints a single form field as required but on model formset it prints 2 by default. Here is my code. models.py class Direction(models.Model): text = models.TextField(blank=True, verbose_name='Direction|text') forms.py class DirectionForm(forms.ModelForm): class Meta: model = Direction fields = ['text',] views.py def myview(request): Dirset = modelformset

Django Formset without instance

不问归期 提交于 2019-12-04 09:43:59
问题 In this Django Doc explain how to create a formset that allows you to edit books belonging to a particular author. What I want to do is: Create a formset that allows you to ADD new book belonging to a NEW author... Add the Book and their Authors in the same formset. Can you gime a light? thanks. 回答1: When you're instantiating the form and formset for the initial display, you don't need to provide an instance - so you will just get blank forms. When you pass in the data on POST, you can do the

Django: How to save a formset based on two models

纵饮孤独 提交于 2019-12-04 09:11:04
I am having difficult times saving a formset to the database. I have 2 models, one having a ForeignKey to the other(I made some entries for Balanta model in Django admin page): models.py class Balanta(models.Model): data=models.DateField() class Meta: ordering=['data'] verbose_name_plural="Balante" def __unicode__(self): return unicode(self.data) class Conturi(models.Model): cont=models.PositiveIntegerField() cont_debit=models.DecimalField(default=0, max_digits=30, decimal_places=2) cont_credit=models.DecimalField(default=0, max_digits=30, decimal_places=2) balanta=models.ForeignKey(Balanta)

Can I use multiple number of formset in a single form in django,if yes how?

六月ゝ 毕业季﹏ 提交于 2019-12-04 06:44:05
I have to make a form in which more than one formset is used. please tell me if this is possible. if yes then how? You can add as many formsets in the form. Just create/init them in view and pass to template to render in the form. Something like: {{ formset1.management_form }} {% for form in formset1 %} {{ form }} {% endfor %} {{ formset2.management_form }} {% for form in formset2 %} {{ form }} {% endfor %} You are using multiple formsets in one view, you need to use prefix for the forms as explained here Using more than one formset in a view In short: article_formset = ArticleFormSet(prefix=

How to access data when form.is_valid() is false

爷,独闯天下 提交于 2019-12-03 05:23:50
问题 When I have a valid Django form, I can access the data with form.cleaned_data. But how do I get at the data a user entered when the form is not valid i.e., form.is_valid is false. I'm trying to access forms within a form set, so form.data seems to just give me a mess. 回答1: You can use form.data['field_name'] This way you get the raw value assigned to the field. 回答2: See http://docs.djangoproject.com/en/dev/ref/forms/validation/#ref-forms-validation Secondly, once we have decided that the

How to access data when form.is_valid() is false

家住魔仙堡 提交于 2019-12-02 19:52:39
When I have a valid Django form, I can access the data with form.cleaned_data. But how do I get at the data a user entered when the form is not valid i.e., form.is_valid is false. I'm trying to access forms within a form set, so form.data seems to just give me a mess. Dmitry Risenberg You can use form.data['field_name'] This way you get the raw value assigned to the field. See http://docs.djangoproject.com/en/dev/ref/forms/validation/#ref-forms-validation Secondly, once we have decided that the combined data in the two fields we are considering aren't valid, we must remember to remove them

Django formset is not valid- why not?

笑着哭i 提交于 2019-12-02 06:34:03
I am trying to use a form to allow users to upload images to projects stored in a database in my Django project, however, I'm currently getting console output that's telling me that the formset I'm using is not valid... The view that I'm trying to use to upload the images to a project has been defined with: def upload_budget_pdfs(request, project_id): project = Project.objects.get(id=project_id) print("Value of project in 'upload_budget_pdfs()': ", project) presentations = project.budget_versions.select_related('meeting').prefetch_related('budget_items', 'cci_items', 'presenters').filter

Django: how to display form errors for each model object in a inline formset

孤者浪人 提交于 2019-11-30 15:27:00
问题 I have a author model and a books model. A user can modify properties of all the books from a given author. I want to be able to display errors for each individual book rather than have all the errors listed on the top, How can I do this? MODELS from django.db import models from django.forms import ModelForm, Textarea from django import forms class Author(models.Model): fname = models.CharField(max_length=100) lname = models.CharField(max_length=100) def fullname(self): return '%s %s' % (self

Django accessing formset data

时光怂恿深爱的人放手 提交于 2019-11-30 14:04:22
问题 I'm having difficulty accessing the data submitted through my formset. Here is my code: Template: <form action="" method="post"> {% csrf_token %} {{ formset.management_form }} {% for form in formset %} {{ form.as_p }} {% endfor %} <input type="submit" value="Submit"> </form> View: def addMembers(request, id, members): if request.user.is_authenticated(): members = int(members) MemberFormSet = formset_factory(MemberForm, extra = members) if request.method == 'POST': print 'post' formset =

Django formset doesn't validate

别等时光非礼了梦想. 提交于 2019-11-30 13:27:36
I am trying to save a formset but it seems to be bypassing is_valid() even though there are required fields. To test this I have a simple form: class AlbumForm(forms.Form): name = forms.CharField(required=True) The view: @login_required def add_album(request, artist): artist = Artist.objects.get(slug__iexact=artist) AlbumFormSet = formset_factory(AlbumForm) if request.method == 'POST': formset = AlbumFormSet(request.POST, request.FILES) if formset.is_valid(): return HttpResponse('worked') else: formset = AlbumFormSet() return render_to_response('submissions/addalbum.html', { 'artist': artist,