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DECLARE @guidList NVARCHAR(max) SELECT @guidList=( CAST(OrderGUID AS nvarchar(max)) +',') FROM OrderWareHouse.dbo.OrderDetail FOR XML PATH('') 将XML Paht('')查询出来的结果赋值给@guidList 变量此时会出错：不允许 ASSIGNMENT 语句中包含 FOR XML 子句。 修改为： set @guidList=(SELECT (CAST(OrderGUID AS nvarchar(max)) +',') FROM OrderWareHouse.dbo.OrderDetail FOR XML PATH('')) PRINT @guidList DECLARE @guidList NVARCHAR(max) SELECT @guidList=( CAST(OrderGUID AS nvarchar(max)) +',') FROM OrderWareHouse.dbo.OrderDetail FOR XML PATH('') 将XML Paht('')查询出来的结果赋值给@guidList 变量此时会出错：不允许 ASSIGNMENT 语句中包含 FOR XML 子句。 修改为： set @guidList=(SELECT

[Python] Unofficial Windows Binaries for Python Extension Packages 1. Unofficial Windows Binaries for Python Extension Packages 非官方的Python第三方库，提供基于Windows的二进制扩展包，由加州大学维护。 2. PyCrypto Prebuilt Python Binaries for Windows PyCrypto提供加密模块，Bottle-corker依赖于该模块。 1. Unofficial Windows Binaries for Python Extension Packages 非官方的Python第三方库，提供基于Windows的二进制扩展包，由加州大学维护。 2. PyCrypto Prebuilt Python Binaries for Windows PyCrypto提供加密模块，Bottle-corker依赖于该模块。 来源： https://www.cnblogs.com/risunlee/p/11915264.html

教程的第一部分主要讲的是mnist_softmax.py里面的代码： 首先是下载和读取mnist数据集，两行代码来实现： from tensorflow.examples.tutorials.mnist import input_data mnist = input_data.read_data_sets("MNIST_data/", one_hot=True) A one-hot vector is a vector which is 0 in most dimensions, and 1 in asingle dimension. 第一行是导入input_data模块，该模块的代码： import tensorflow as tf from tensorflow.contrib.learn.python.learn.datasets.mnist import read_data_sets 发现其实没有直接的input_data.read_data_sets()函数，而是又导入了另一个模块，该模块名叫read_data_sets，找到这个文件，里面的代码是： def read_data_sets(train_dir, fake_data=False, one_hot=False, dtype=dtypes.float32, reshape=True, validation

import getpass username = input("please input your name:") password = getpass.getpass("please input the password:") fo = open("homework01.txt","a+") print(username) print(password) fo.write(username) fo.write(password) fo_read = fo.read() print(fo_read) fo.close() Console: please input your name:Ansue please input the password:123456 Ansue 123456 .....hello也无法写入 来源： https://www.cnblogs.com/ansue-home/p/11886460.html

java.sql.SQLException: Access denied for user 'root'@'10.1.0.2' (using password: YES) at com.mysql.cj.jdbc.exceptions.SQLError.createSQLException(SQLError.java:129) at com.mysql.cj.jdbc.exceptions.SQLError.createSQLException(SQLError.java:97) at com.mysql.cj.jdbc.exceptions.SQLExceptionsMapping.translateException(SQLExceptionsMapping.java:122) at com.mysql.cj.jdbc.ConnectionImpl.createNewIO(ConnectionImpl.java:835) at com.mysql.cj.jdbc.ConnectionImpl.<init>(ConnectionImpl.java:455) at com.mysql.cj.jdbc.ConnectionImpl.getInstance(ConnectionImpl.java:240) at com.mysql.cj.jdbc

E 给出三个序列共n个元素，每个元素值为1~n且不重 一次可以把一个元素换到另一个序列中，求最少操作次数使得三个序列（可为空）分别排序后并在一起为1~n顺序 题解 (伪)神仙题 随便dp，依次考虑每个数放在那里 由于要保证最终的顺序，所以放的序列的编号要单调 f[i][0/1/2]，第i个放在0/1/2的最小操作数 code #include <algorithm> #include <iostream> #include <cstdlib> #include <cstring> #include <cstdio> #define fo(a,b,c) for (a=b; a<=c; a++) #define fd(a,b,c) for (a=b; a>=c; a--) #define min(a,b) (a<b?a:b) using namespace std; int a[200002]; int f[200002][3]; int n,n1,n2,n3,i,j,k,l,ans,Ans; int main() { // freopen("e.in","r",stdin); scanf("%d%d%d",&n1,&n2,&n3);n=n1+n2+n3; fo(i,1,n1) scanf("%d",&j),a[j]=0; fo(i,1,n2) scanf("%d",&j),a[j]

1、 Docker 挂载主机目录，访问相应的文件出现Premission denied的权限访问问题 问题原因及解决办法 原因是CentOS7中的安全模块selinux把权限禁掉了，主要是挂载的目录没有权限的问题 2、 添加selinux规则，改变要挂载的目录的安全性文本 chcon -Rt svirt_sandbox_file_t /home/hct/sample/ 来源： CSDN 作者： 椰汁菠萝 链接： https://blog.csdn.net/suo082407128/article/details/83348639

BMW ICOM A2+B+C is upgrade of BMW ICOM, ICOM A2 is Second generation of BMW ISTA Diagnose and programming system. Support both new and old BMW vehicles. BMW ICOM A2 : Software Version : 2016.07 ISTA/D (ISID /DiagnosticISTA-D 3.55.31 ISTA-P 3.59.0.600 VIN: 2016.06.15 BMW ICOM : 1. Support Multi-language: American English, British English, German, Spanish, French, Italian, Polish, Portuguese, Turkish, Czech, Swedish, Dutch, Indian, Greek, Russian, Japanese, Korean, Thai, Simplified Chinese and Traditional Chinese 2. Hardware Version: ICOM Application-01.40.05 3. Support Vehicles: BMW Cars, BMW

Anroid Firebase Project setup: 1. In firebase console, cerate a Android app setup you can find in code: Find "applicationId", undef "defaultConfig", put to website. 2. Click "Regsiter App" 3. Download google-services.json 4. Copy to android/app folder 5. Click "Next" to continue 6. Open "android/build.gradle": buildscript { repositories { google() // Add this line jcenter() } dependencies { classpath 'com.android.tools.build:gradle:3.2.1' classpath 'com.google.gms:google-services:4.3.2' // Add this line } } 7. Open "android/app/build.gradle": dependencies { testImplementation 'junit:junit:4.12

Contest14的本质：区间覆盖+Tarjan（ A 把距离公式两边平方即可 注意要long long code #include <algorithm> #include <iostream> #include <cstdlib> #include <cstring> #include <cstdio> #define fo(a,b,c) for (a=b; a<=c; a++) #define fd(a,b,c) for (a=b; a>=c; a--) using namespace std; int x[100001]; int y[100001]; int n,i,j,k,l,X,Y,R,ans; int main() { // freopen("a.in","r",stdin); scanf("%d%d%d%d",&n,&X,&Y,&R); fo(i,1,n) scanf("%d%d",&x[i],&y[i]); fo(i,1,n) if (((long long)(x[i]-X)*(x[i]-X)+(long long)(y[i]-Y)*(y[i]-Y))<=(long long)R*R) ++ans; printf("%d\n",ans); } B 显然p和k是位置最靠边的两个 考虑一下i和n的位置（靠左/靠右/左右） code 比较丑 #include