fetchall

Quick PHP/MySQL question: I'm trying to display the data from a MySQL database table as an HTML table, and for some reason my code doubling the output of each piece of data. This is my code: $rowarray = $statement->fetchall(); print "<tr>\n"; foreach ($rowarray as $row) { foreach ($row as $col) { print "\t<td>$col</td>\n"; } print "</tr>\n"; } My results look something similar to this: User ID | User Name | First Name | Last Name 1 1 User Name User Name First Name First Name Last Name Last Name Etc etc. You get the idea. Why this is happening? By the way, if I manually add the column

I'm trying to use fetchAll on a query that has 2 variables. I can't figure out the syntax. I can manage with only 1 variable: $sql = "SELECT * FROM mytable WHERE field1 = ?"; $this->_db->fetchAll($sql,$value1); # that works However I'm having some issues when query has multiple variables $sql = "SELECT * FROM mytable WHERE field1 = ? AND field2 = ?"; $this->_db->fetchAll($sql,$value1,$value2); # doesn't work $this->_db->fetchAll($sql,array("field1"=>$value1,"field2"=>$value2)); # doesn't work either The reason why I want to use ? instead of placing the variables directly into the query is that