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来源： https://stackoverflow.com/questions/64228366/cannot-call-google-cloud-function-behind-firebase-hosting-status-503-but-no-in

来源： https://stackoverflow.com/questions/64228366/cannot-call-google-cloud-function-behind-firebase-hosting-status-503-but-no-in

问题 I'm curious if there is a way rewrite a URL if response is a 404, in Varnish 2.1.5? For example. I'd like to pull up a URL, which may or may not exist. If the URL doesn't exist, I'd like to do a URL rewrite and try the new URL instead. I'm new to Varnish and don't completely understand the lifecycle of a request (if anyone knows a guy of article explaining this, please share). I've tried setting some variables and request headers, and checking res.status but they seem to get lost someplace in

问题 I am trying to redirect a path e.g. www.something.com/apple/pie to www.something.com/tickets/pie-details but also have some exceptions e.g. www.something.com/apple/helloworld does not get redirected to www.something.com/tickets/helloworld-details This is what I have tried but doesn't work: if (req.url ~ "^/apple/.*" && req.url != "^/apple/helloworld") { set req.url = "^/tickets/.*-details"; error 701 req.url; } 回答1: https://info.varnish-software.com/blog/rewriting-urls-with-varnish