evaluate

Why doesn't my properly defined variable evaluate for length correctly (and subsequently work in the rest of my code)?

狂风中的少年 提交于 2020-01-06 14:18:00
问题 I employed the answer Marc B suggested and still got nothing in the variable when I echo'd it after the while loop, so I added a few checks to show status of things as they were processed through the code. When the if/else statement runs next, it shows the result that there is length to the variable. The next if/else statement branches to the else statement and then takes the else statement in the next if/else saying the xpath found nothing. So obviously when I go to use the variable $BEmp3s,

Why doesn't my properly defined variable evaluate for length correctly (and subsequently work in the rest of my code)?

六眼飞鱼酱① 提交于 2020-01-06 14:17:09
问题 I employed the answer Marc B suggested and still got nothing in the variable when I echo'd it after the while loop, so I added a few checks to show status of things as they were processed through the code. When the if/else statement runs next, it shows the result that there is length to the variable. The next if/else statement branches to the else statement and then takes the else statement in the next if/else saying the xpath found nothing. So obviously when I go to use the variable $BEmp3s,

VBA - How to get the result of a formula ? (.Value always returns 0)

霸气de小男生 提交于 2020-01-06 04:04:23
问题 I want to get the result of a formula contained in a cell, but I always get 0 returned, instead of the real results. I have the following: Set c = .Cells (5,5) MsgBox (c.Formula) ' this return the following: = ASIN (W22-V22/$D$7)*180/PI() MsgBox (c.Value) ' this returns 0 MsgBox (c.Value2) ' this returns 0 as well And even if I try with Evaluate: evaluation = Application.Evaluate (c.Formula) MsgBox (c.Value) ' it still returns 0 回答1: Zero is the correct answer if both V22 and W22 are zero.

VBA - How to get the result of a formula ? (.Value always returns 0)

坚强是说给别人听的谎言 提交于 2020-01-06 04:03:09
问题 I want to get the result of a formula contained in a cell, but I always get 0 returned, instead of the real results. I have the following: Set c = .Cells (5,5) MsgBox (c.Formula) ' this return the following: = ASIN (W22-V22/$D$7)*180/PI() MsgBox (c.Value) ' this returns 0 MsgBox (c.Value2) ' this returns 0 as well And even if I try with Evaluate: evaluation = Application.Evaluate (c.Formula) MsgBox (c.Value) ' it still returns 0 回答1: Zero is the correct answer if both V22 and W22 are zero.

Evaluate code, differentiating between minus and negative?

旧城冷巷雨未停 提交于 2020-01-06 02:58:25
问题 I am working on evaluating an expression, and I am running into trouble inputting negative numbers. Due to the structure of my code, and the fact that a subtraction operator and a negative sign are the same character, my code doesn't work for negative numbers. Is there a way to work around this? private float evalNoPB(String s) { float tempAns = 0; if (s.contains("*") == false && s.contains("/") == false && s.contains("+") == false && s.contains("-") == false) { return Float.parseFloat(s); }

Passing js Variable to html file GAS - BASIC

我们两清 提交于 2019-12-30 10:38:07
问题 I'm trying to pass a variable (my name in cell A1) from my code.gs to my Index.html and email it. Can someone please tell me what I'm doing wrong or point me in the right direction. Code.gs function doGet() { return HtmlService.createHtmlOutputFromFile('Index'); } function sendEmail() { var ss = SpreadsheetApp.openById('MY_SPREADSHEET_ID'); var sheet = ss.getSheetByName('Sheet1'); var myName = sheet.getRange(1,1).getValue(); var template = HtmlService.createTemplateFromFile('Index'); var body

Need Groovy syntax help for generating a Closure from a String

扶醉桌前 提交于 2019-12-29 09:14:26
问题 I'm trying to generate a closure from a string. The code inside the closure references a DSL function build(). The errors I'm getting imply that Groovy is trying to execute the closure instead of just declaring it. What is the correct syntax for this? Here are some of the constructs I have already tried. sh = new GroovyShell() cl = sh.evaluate( '{ build("my job") }' } => Ambiguous expression could be either a parameterless closure expression or an isolated open code block; sh = new

Convert string into operator in Scala

我们两清 提交于 2019-12-25 14:29:41
问题 How can I convert a string in Scala into a corresponding operator? Given two integers and the string "+" I want the result of adding these two integers. 回答1: The last question is very simple: def applyOperator(x: Int, y: Int, operator: String) = operator match { case "+" => x + y case "-" => x - y ... } You could try using Twitter's Eval library or reflection, but I wouldn't recommend it given the simpler solution. For the first question: operators themselves aren't values, so you can't

Evaluate mathematical expression within string

倾然丶 夕夏残阳落幕 提交于 2019-12-25 08:57:13
问题 I'm developing an Android app that i get an String with the mathematical expression i have to calculate, i did it to convert the letters into the numbers i need, but what is the best way to evaluate this? Nothing too complicated, the formulas are like those: ((A * 2 + B * 3 + C * 5) / 10) + D EDIT: Just found that guy, very simple API, works like a charm http://code.google.com/p/symja/wiki/MathExpressionParser 回答1: You want some sort of math parser. Fun to roll your own, or there are plenty

JavaScript for replacing text in the body tag of pages loaded into an open source browser for Android

混江龙づ霸主 提交于 2019-12-25 07:59:10
问题 I'm writing a JavaScript for an open source browser available for Android to replace the text in the body tag of the pages loaded into the browser with some different text. This should be worked in away that once a page get loaded into the browser, this JavaScript executes & the replacements take place & finally the page with replaced text is visible in the browser. This is the replacing part of the code: var textnodes, node, i; textnodes = document.evaluate("//body//text()[not(ancestor: