equations

Find equations in word and save each out as separate file

由 。_饼干妹妹 提交于 2019-12-11 08:34:48
问题 I would like to go through a Word doc, using vba, to take each equation, save it to the clipboard, open a new blank doc, and save that out as a pdf file. I found two pieces of code which should help me get started but neither get very far: Sub get_eqns() Dim eqns As OMath Dim para As Paragraph For Each eqns In ActiveDocument.OMaths With eqns.Range.Select ' '~~> Rest of the code ' End With Next For Each para In ActiveDocument.Paragraphs If para.Range.OMaths(1) = True Then para.Range.OMaths(1)

How to parse mathML in output of WordOpenXML?

由 心已入冬 提交于 2019-12-09 13:13:28
问题 I want to read only the xml used for generating equation, which i obtained by using Paragraph.Range.WordOpenXML . But the section used for the equation is not as per MathML which as i found that the Equation of microsoft is in MathML . Do I need to use some special converter to get desired xmls or are there any other methods? 回答1: You could use the OMML2MML.XSL file (located under %ProgramFiles%\Microsoft Office\Office15 ) to transform Microsoft Office MathML (equations) included in a word

Solving system of equations using matlab

由 耗尽温柔 提交于 2019-12-07 12:46:26
问题 So I have the following system of equations x1 - x2 = 20 x2 - x3 = 30 x3 - x4 = 75 x4 - x5 = -49 -x1 + x5 = -20 how would I solve the system using Matlab? I I'm a little stuck. There's a good chance there's no solution but if someone could let me know how to do it that would be great! 回答1: First, convert this equation into matrix notation: A = [ 1 -1 0 0 0 0 1 -1 0 0 0 0 1 -1 0 0 0 0 1 -1 -1 0 0 0 1]; b = [ 20 30 75 -49 -20]; You are trying to find x giving Ax = b . You can not take the

Using scipy sparse matrices to solve system of equations

由 本小妞迷上赌 提交于 2019-12-07 03:34:04
问题 This is a follow up to How to set up and solve simultaneous equations in python but I feel deserves its own reputation points for any answer. For a fixed integer n , I have a set of 2(n-1) simultaneous equations as follows. M(p) = 1+((n-p-1)/n)*M(n-1) + (2/n)*N(p-1) + ((p-1)/n)*M(p-1) N(p) = 1+((n-p-1)/n)*M(n-1) + (p/n)*N(p-1) M(1) = 1+((n-2)/n)*M(n-1) + (2/n)*N(0) N(0) = 1+((n-1)/n)*M(n-1) M(p) is defined for 1 <= p <= n-1 . N(p) is defined for 0 <= p <= n-2 . Notice also that p is just a

How to show math equations in QTextEdit?

由 ♀尐吖头ヾ 提交于 2019-12-06 01:12:43
问题 Does anyone know how to show mathematical equations in QTextEdit written in any format (TXT, MathML, MML, LaTeX, HTML, XML or anything) using only Python, that is without using 3rd party packages like Latex itself.? I tried to find the MathML Widget from Qt but it disappeared from their web site and I couldn't find it anywhere. I'm not fussed about the equation source (either a string or a file). I just can't figure out how to show them nicely (the same way as they appear on a web page, e.g.

Solving system of equations using matlab

由 試著忘記壹切 提交于 2019-12-05 19:49:50
So I have the following system of equations x1 - x2 = 20 x2 - x3 = 30 x3 - x4 = 75 x4 - x5 = -49 -x1 + x5 = -20 how would I solve the system using Matlab? I I'm a little stuck. There's a good chance there's no solution but if someone could let me know how to do it that would be great! First, convert this equation into matrix notation: A = [ 1 -1 0 0 0 0 1 -1 0 0 0 0 1 -1 0 0 0 0 1 -1 -1 0 0 0 1]; b = [ 20 30 75 -49 -20]; You are trying to find x giving Ax = b . You can not take the inverse of A since it is singular. To see this check its rank; rank(A) == 4 . It would be 5 if A were non

Equation Threading: Why the default behavior?

由 会有一股神秘感。 提交于 2019-12-05 12:52:34
问题 I recently rediscovered a small package by Roman Maeder that tells Mathematica to automatically thread arithmetic and similar functions over expressions such as x == y. Link to Maeder's package. First, to demonstrate, here's an example given by Maeder: In[1]:= Needs["EqualThread`"] Now proceed to use the threading behavior to solve the following equation for x 'by hand': In[7]:= a == b Log[2 x] In[8]:= %/b Out[8]:= a/b == Log[2 x] Now exponentiate: In[9]:= Exp[%] Out[9]= E^(a/b) == 2 x And

Using scipy sparse matrices to solve system of equations

由 江枫思渺然 提交于 2019-12-05 08:19:54
This is a follow up to How to set up and solve simultaneous equations in python but I feel deserves its own reputation points for any answer. For a fixed integer n , I have a set of 2(n-1) simultaneous equations as follows. M(p) = 1+((n-p-1)/n)*M(n-1) + (2/n)*N(p-1) + ((p-1)/n)*M(p-1) N(p) = 1+((n-p-1)/n)*M(n-1) + (p/n)*N(p-1) M(1) = 1+((n-2)/n)*M(n-1) + (2/n)*N(0) N(0) = 1+((n-1)/n)*M(n-1) M(p) is defined for 1 <= p <= n-1 . N(p) is defined for 0 <= p <= n-2 . Notice also that p is just a constant integer in every equation so the whole system is linear. Some very nice answers were given for

Convert Expression from a Textbox to Math Expression in Code Behind [duplicate]

由 廉价感情. 提交于 2019-12-04 14:24:06
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: I need a fast runtime expression parser How do I make it that when someone types in x*y^z in a textbox on my page to calculate that equation in the code behind and get the result? 回答1: .NET does not have a built-in function for evaluating arbitrary strings. However, an open source .NET library named NCalc does. NCalc is a mathematical expressions evaluator in .NET. NCalc can parse any expression and evaluate the

Python solve equation for one variable

由 南笙酒味 提交于 2019-12-04 09:37:25
问题 I'm trying to solve an equation in python using SymPy. I have a generated equation (something like function = y(8.0-(y**3.0)) which I use with SymPy to create a new equation like this: eq = sympy.Eq(function, 2) which outputs y(8.0-(y**3.0)) == 2 . but sympy.solve(eq) doesn't seem to work. >>> from sympy import Eq, Symbol as sym, solve >>> y = sym('y') >>> eqa = Eq(y(8.0-(y**3.0)), 8) >>> solve(eqa) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib
订阅 equations