ends-with

I have a string: myStr = "Chicago Blackhawks vs. New York Rangers" I also have a list: myList = ["Toronto Maple Leafs", "New York Rangers"] Using the endswith() method, I want to write an if statement that checks to see if the myString has ends with either of the strings in the myList. I have the basic if statement, but I am confused on what I should put in the parentheses to check this. if myStr.endswith(): print("Success") endswith() accepts a tuple of suffixes. You can either convert your list to a tuple or just use a tuple at the first place: >>> myStr = "Chicago Blackhawks vs. New York

I'm looking for the best most efficient way to match the end of a single string with a value from a predefined list of strings. Something like my_str='QWERTY' my_lst=['QWE','QQQQ','TYE','YTR','TY'] match='TY' or match=['TY'] Under the restrictions len(my_lst) is known but arbitrary thus could be very long, probably around 30 elements in my_lst may have different len so I can't just check a defined last portion of my_str every time for my_str as well as the matching elements in my_lst they can be either strings or lists, whichever is more efficient (see background) len(my_str) is mostly small,

This question already has an answer here: startsWith() method of string ignoring case 7 answers Here's my code: public static void rightSel(Scanner scanner,char t) { /*if (!stopping)*/System.out.print(": "); if (scanner.hasNextLine()) { String orInput = scanner.nextLine; if (orInput.equalsIgnoreCase("help") { System.out.println("The following commands are available:"); System.out.println(" 'help' : displays this menu"); System.out.println(" 'stop' : stops the program"); System.out.println(" 'topleft' : makes right triangle alligned left and to the top"); System.out.println(" 'topright' : makes

The question is very clear in the title. As added to base in 3.3.0 , startsWith (and endsWith ) are exactly this. > startsWith("what", "wha") [1] TRUE > startsWith("what", "ha") [1] FALSE https://stat.ethz.ch/R-manual/R-devel/library/base/html/startsWith.html Not inbuilt like that. Options include grepl and substr . x <- 'ABCDE' grepl('^AB', x) # starts with AB? grepl('DE$', x) # ends with DE? substr(x, 1, 2) == 'AB' substr('ABCDE', nchar(x)-1, nchar(x)) == 'DE' The dplyr package's select statement supports starts_with and ends_with . For example, this selects the columns of the iris data

How can I find out if a string ends with another string in C++? kdt Simply compare the last n characters using std::string::compare : #include <iostream> bool hasEnding (std::string const &fullString, std::string const &ending) { if (fullString.length() >= ending.length()) { return (0 == fullString.compare (fullString.length() - ending.length(), ending.length(), ending)); } else { return false; } } int main () { std::string test1 = "binary"; std::string test2 = "unary"; std::string test3 = "tertiary"; std::string test4 = "ry"; std::string ending = "nary"; std::cout << hasEnding (test1, ending)

I am trying to find an input element with dynamic id name always ending with "register". So far I tried this "//input[@id[ends-with(.,'register')]]" and this "//input[ends-with(@id,'register')]" none of these result in an element. What am I doing wrong? At the same time this works: "//input[@id[contains(.,'register')]]" Here's the part of source: <td class="input"> <input id="m.f0.menu.f2.volumeTabs.BLOCK_COMMON.tcw.form.register" name="m.f0.menu.f2.volumeTabs.BLOCK_COMMON.tcw.form.register" class="aranea-checkbox" type="checkbox"> </td> The ends-with function is part of xpath 2.0 but browsers