do-while

Do while Loop to show a menu

给你一囗甜甜゛ 提交于 2020-12-31 20:01:33
问题 I have created my menu with do~while(true); but every time the user insert a number, instead of running the program it shows the the menu again! what do you think? // my main method public static void main(String[] args) { DataReader reader = new DataReader(); // The reader is used to read data from a file // Load data from the file if(reader.loadData(args[0])) { // The filename is entered using a command-line argument vehicles= reader.getVehicleData(); // Store the arrays of Vehicle //

Why there is no output or blank output for this java code containing “do while” loop? [closed]

有些话、适合烂在心里 提交于 2020-08-20 14:42:41
问题 Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 days ago . Improve this question Can you please explain why there is no output or blank output for the following java code containing do while loop? public class Main { public static void main(String[] args) { int i = 10; do while ( i < 10 ) System.out.print("The value of i is " + i); while ( i

Why there is no output or blank output for this java code containing “do while” loop? [closed]

被刻印的时光 ゝ 提交于 2020-08-20 14:41:33
问题 Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 days ago . Improve this question Can you please explain why there is no output or blank output for the following java code containing do while loop? public class Main { public static void main(String[] args) { int i = 10; do while ( i < 10 ) System.out.print("The value of i is " + i); while ( i

Bash if condition to check variable for changes over time

喜你入骨 提交于 2020-07-30 04:12:08
问题 Wondering if it's possible to finagle this logic (checking a variable for changes over time and running a loop while true) into a bash if statement or while loop condition. I was hoping for something like: var=$(du -h *flat*.vmdk) var2=$(sleep 1 ; du -h *flat*.vmdk) if [[ $var != $var2 ]]; then while true do echo -ne $(du -h *flat*.vmdk)\\r sleep 1 done else echo "Transfer complete" fi I've also played with a while loop , rather than an if then with no luck. while [ $var != $var2 ] ; do echo

Bash if condition to check variable for changes over time

一世执手 提交于 2020-07-30 04:10:07
问题 Wondering if it's possible to finagle this logic (checking a variable for changes over time and running a loop while true) into a bash if statement or while loop condition. I was hoping for something like: var=$(du -h *flat*.vmdk) var2=$(sleep 1 ; du -h *flat*.vmdk) if [[ $var != $var2 ]]; then while true do echo -ne $(du -h *flat*.vmdk)\\r sleep 1 done else echo "Transfer complete" fi I've also played with a while loop , rather than an if then with no luck. while [ $var != $var2 ] ; do echo

How to get out this Do-While loop?

♀尐吖头ヾ 提交于 2020-06-16 03:00:08
问题 I've this basic Arduino code, and I want to have 2 options to exit this Do-While loop . I simplified my original code to highlight the real problem: the Do-While doesn't recognize the OR || condition to exit the loop In this code I'm starting with two integer variables that are equal to zero and as soon as they enter the Do-While, they'will be setted equal to 2 both, so that they can immediately exit the Do-While in the first iteration. Here's my code: int fin = 0; int ending = 0; int counter

Non Duplicate number in user input [duplicate]

久未见 提交于 2020-04-17 22:51:48
问题 This question already has answers here : Non duplicates numbers in user input (5 answers) Closed last month . With this Lottery program I am trying to make sure the number are within a range of 1-59, The same number cannot be entered twice and that only numbers can be entered. The only bit of code I need help on is on the only numbers can be entered part. public void choose() { System.out.println("\n"); int temp; boolean valid; for (int i = 0; i < 6; i++) { do { valid = true; System.out.print

Non Duplicate number in user input [duplicate]

。_饼干妹妹 提交于 2020-04-17 22:50:39
问题 This question already has answers here : Non duplicates numbers in user input (5 answers) Closed last month . With this Lottery program I am trying to make sure the number are within a range of 1-59, The same number cannot be entered twice and that only numbers can be entered. The only bit of code I need help on is on the only numbers can be entered part. public void choose() { System.out.println("\n"); int temp; boolean valid; for (int i = 0; i < 6; i++) { do { valid = true; System.out.print