digits

问题 My question is this. I can say in xml android:digits="0123456789," But this time I've to it add trough java code. customEditText.setKeyListener(DigitsKeyListener.getInstance("0123456789,")); Doesn't work. Application gives me same result as android:InputType="number" So is there any alternative way to say android:digits using java? EDITED So my question wasn't how to get android:InputType="number" using java. My question is that how I can get android:digits="0123456789," to be used with java.

问题 My question may seem simple, but still can not get something that works. I need to customize the Math.round rounding format or something to make it work as follows: If the number is 1.6 he should round to 1, if greater than or equal to 1.7 should round to 2.0 . And so to all other decimal results with # .6 The way I'm doing the 1.6 being rounded to 2 shall be rounded to 1. How can I do that? Thank you! 回答1: Simply do this: double threshold = 0.7; Math.round(x - threshold + 0.5); 回答2: You

问题 In matlab I want to convert this: 12345.6788993442355456789 into a vector [1 2 3 4 5 6 7 8 8 9 9 3 4 4 2 3 5 5 4 5 6 7 8 9] I have found several solutions to convert a integer into a vector using commands like scanf, num2str,... but those don't fit with non-integers, and some solutions have problems with numbers with a large number of decimal places... That kind of conversion is needed because I want to see and use all of the digits of the number. 回答1: What input source are you getting those

问题 How can we find the number of numbers less than a given number with no repeating digits in it? For example the number of such numbers less than 100 is 90. (11, 22, 33,44, 55,66,77,88,99 have repeating digits so are excluded). Similarly for less than 1000, digits like 101, 110, 122, 202 etc have to be excluded. 回答1: Here is a way to make it quicker. Notice that there is a correlation between the number of digits in the max number and the solution (number of numbers which I will call NON ) 100

问题 I am trying to test if the decimal representation of a certain number contains the digit 9 at least twice, so I decided to do something like that: i=98759102 string=str(i) if '9' in string.replace(9, '', 1): print("y") else: print("n") But Python always responds with "TypeError: Can't convert 'int' object to str implicitly". What am I doing wrong here? Is there actually a smarter method to detect how often a certain digit is contained in the decimal representation of an integer? 回答1: Your

问题 I found this code for making my textbox only accept numbers. Private Sub TextBox1_KeyPress(ByVal sender As System.Object, ByVal e As System.Windows.Forms.KeyPressEventArgs) Handles TextBox1.KeyPress Dim allowedChars As String = "0123456789" If allowedChars.IndexOf(e.KeyChar) = -1 Then ' Invalid Character e.Handled = True End If End Sub But... the user can't delete the numbers using the backspace button. How do I do then? 回答1: You also need to handle pasted text (there may not be a keypress).

问题 I am unsure about how to generate a random n digit integer in Java using the BigInteger class. 回答1: private static Random rnd = new Random(); public static String getRandomNumber(int digCount) { StringBuilder sb = new StringBuilder(digCount); for(int i=0; i < digCount; i++) sb.append((char)('0' + rnd.nextInt(10))); return sb.toString(); } And then you can use it: new BigInteger(getRandomNumber(10000)) 回答2: According to the docs, there is a constructor to do what you want in java 6: BigInteger

问题 I have to set acceptable characters "0123456789" and "semicolon" in the EditText. Below is the code I'm using. android:digits="0123456789;" android:inputType="number|text The problem with that implementation is in HTC phones, semicolon can't be entered but in Samsung and Sony Ericsson, semicolon can be entered. Another problem is when I entered semicolon in Samsung and Sony Ericsson, semicolon can't be deleted. Is there any missing property in the above code? Thanks in advance. 回答1: Android

问题 I want to make a function, which returns true whenever two numbers provided on input are made up of the same digits (with no replacement). For example, 543 and 435 should return true, 10001 and 11000 should return true, but 111222 and 122222 should return false. I've read something about bitmasks but do not really get it, could You help me? 回答1: The simplest way I can think to handle this is to use buckets. Create an std::vector of length 10 (one for each digit) and then increment an index

问题 Can anyone please tell me how to multiply two number arrays in C? The number arrays are basically derived from two strings containing digits. eg: 123456 and 132465. Edit: I had two string as S1 = "123456" and S2="132546" . I then converted these two strings into array of ints i.e. int IS1[6] and IS2[6] so that IS1[1] = 1, IS1[2] = 2...... and IS2[1] = 1, IS2[2] = 3..... Now I have to mulitply these two arrrays. Please help. 回答1: It's not clear what exactly you want to multiply. If you need to