difference

问题 I have: var now = moment.format(); //get current time var days = 5; //days I need to subtract from time(then) var then = '05/02/2016 12:00 am'; Now I need to get difference between now and then substract(-) 5 days but in +0000 so GMT +0. so now must be in user localtime and then must be at +0000 GMT. How I can get difference between this dates in days, hours, minutes, seconds? I try: var now = moment().format(); var then = moment('05/02/2016 12:00 am').utcOffset(+0000).format(); then = moment

问题 I am using Pycharm to run my pytest unit tests. I am testing a REST API, so I often have to validate blocks of JSON. When a test fails, I'll see something like this: FAILED test_document_api.py:0 (test_create_documents) {'items': [{'i...ages': 1, ...} != {'items': [{'...ages': 1, ...} Expected :{'items': [{'...ages': 1, ...} Actual :{'items': [{'i...ages': 1, ...} <Click to see difference> When I click on the "Click to see difference" link, most of the difference is converted to points of

问题 I have a data.frame with many rows and columns and I want to calculate the mean difference of each value to each of the other values within a group. Here an example: ID value 1 4 1 5 1 7 2 8 2 6 2 5 2 6 This is what I want to calculate: ID value value_mean_diff 1 4 (4-5)^2 + (4-7)^2 /groupsize = 3 1 5 (5-4)^2 + (5-7)^2 / 3 1 7 (7-4)^2 + (7-5)^2 / 3 2 8 (8-6)^2 + (8-5)^2 + (8-6)^2 / 4 2 6 (6-8)^2 + (6-5)^2 + (6-6)^2 / 4 2 5 (5-8)^2 + (5-6)^2 + (5-6)^2 / 4 2 6 (6-8)^2 + (6-6)^2 + (6-5)^2 / 4 I

问题 I want make 2 different colors on the output image when using Imagemagick. I have an original image with "Hello World" in it. And a modified image with "Hello Warcraft" in the same area. The default compare command will give me a image and mark all the differences with red. Now I want to use 2 different colors like "orld" marked as red, and "arcraft" marked as another color, maybe blue. Is ImageMagick able to do this? If not, how to use ImageMagick to transfer a specified color to another one

问题 I found some similar questions such as this one (about comparing attributes in XML files), this one (about a case where the compared values are numeric) and this one (about getting a number of columns that differ between two files) but nothing about this particular problem. I have two CSV text files on which many, but not all, rows are equal. The files have the same amount of columns with same data type on the columns but they do not have the same amount of rows. The amount of rows on both

问题 I am trying to substract two pandas dataframes from each other, but get only NaN results: Dataframe 1: alpha beta 0 1 4 1 2 5 2 3 6 Dataframe 2: gamma 0 7 1 8 2 9 Dataframe operation: df3=df1-df2 Result: alpha beta gamma 0 NaN NaN NaN 1 NaN NaN NaN 2 NaN NaN NaN However, if I convert everything to numpy matrices, it works: Matrix operation: matrix3=df1.as_matrix(['alpha','beta'])-df2.as_matrix(['gamma']) Result: [[-6 -3] [-6 -3] [-6 -3]] How can I make this work with pandas? 回答1: Either of

问题 I didn't find any fast algorithm for getting quad-trees differences in following format. Let's say that we have two arbitrary 4 level trees: var tree1 = [ { id: "1.1", children: [ { id: "1.1.1", children: null }, { id: "1.1.2", children: null }, { id: "1.1.3", children: [ { id: "1.1.3.1", children: null }, { id: "1.1.3.2", children: null }, { id: "1.1.3.3", children: null }, { id: "1.1.3.4", children: null } ] }, { id: "1.1.4", children: null } ] }, { id: "1.2", children: null }, { id: "1.3",

问题 23:59:59 o'clock is closer to midnight than 03:00:00 o'clock to midnight, for example. Unfortunately, R tells the opposite (at least the package I use). Here is what I mean: In fact I do not only care about midnight but I need to find the closest time of the day in a vector to a given time and I do not care about the date. There is a similiar question with a great answer but the code doesn't work as expected because in the link time is a timeline not a circle. See here: library("chron") x <-

来源： https://stackoverflow.com/questions/54505175/calculating-second-order-derivative-from-timeseries-using-pandas-diff

来源： https://stackoverflow.com/questions/54505175/calculating-second-order-derivative-from-timeseries-using-pandas-diff