diamond-operator

Why can't Java 7 diamond operator be used with anonymous classes?

纵然是瞬间 提交于 2019-11-28 07:12:01
Consider this Java code which attempts to instantiate some List s: List<String> list1 = new ArrayList<String>(); List<String> list2 = new ArrayList<>(); List<String> list3 = new ArrayList<String>() { }; List<String> list4 = new ArrayList<>() { }; List<String> list5 = new ArrayList<Integer>() { }; list1 and list2 are straightforward; list2 uses the new diamond operator in Java 7 to reduce unnecessary repetition of the type parameters. list3 is a variation on list1 using an anonymous class, potentially to override some methods of ArrayList . list4 attempts to use the diamond operator, similar to

Java 10: Will Java 7's Diamond Inference Work with Local Type Inference?

偶尔善良 提交于 2019-11-27 14:21:03
问题 From JEP 286, we see that we'll be able to utilize local type inference ( var ) in JDK 10 (18.3). The JEP states that the following compiles, which is expected: var list = new ArrayList<String>(); // infers ArrayList<String> I'm curious to know what would happen if we attempt the following: var list = new ArrayList<>(); Will what I proposed in the second snippet even compile? If so (which I doubt), would the ArrayList accept Object as its generic type? I'd try this myself, but I don't have

getting compile error for diamond operator in idea ide

匆匆过客 提交于 2019-11-27 05:24:27
I am getting this error while trying to compile some simple source code in idea ide. java: diamond operator is not supported in -source 1.6 (use -source 7 or higher to enable diamond operator) jdk is 1.7.40 from oracle but where is this place to add this "-source 7" option? i tried adding in ide settings but that had no effect. You need to set the project language level (default for all modules) and the module(s) language level Make sure that, in the Project Structure page, you have set your project language level to 7.0. After you select this, you will have to reopen your project, but then

Why diamond operator is used for Type Inference in Java 7?

安稳与你 提交于 2019-11-26 20:57:08
问题 List<String> list = new ArrayList(); will result in compiler warning. However the following example compiles without any warning: List<String> list = new ArrayList<>(); I'm curious why introducing of diamond operator is needed at all. Why not just have type inference on constructor if type argument is absent (as its already done for static methods in java and exploited by collection libraries like google guava) EDIT : Using millimoose answer as starting point I looked what type erasure

What is the diamond operator in Java? [duplicate]

不羁的心 提交于 2019-11-26 14:41:27
This question already has an answer here: What is the point of the diamond operator (<>) in Java 7? 7 answers I have an arraylist with type patient_class and the arraylist type has been underlined in yellow and the IDE has mentioned "redundant type arguments in new expression (use diamond operator instead)". My problem is: Should I use the diamond operator instead? Is it a must? Will I get any data loss or any other problem when storing records to the arraylist? Here is my arraylist: public class Register_newpatient extends javax.swing.JFrame { public Register_newpatient() { initComponents();

getting compile error for diamond operator in idea ide

帅比萌擦擦* 提交于 2019-11-26 11:35:35
问题 I am getting this error while trying to compile some simple source code in idea ide. java: diamond operator is not supported in -source 1.6 (use -source 7 or higher to enable diamond operator) jdk is 1.7.40 from oracle but where is this place to add this \"-source 7\" option? i tried adding in ide settings but that had no effect. 回答1: You need to set the project language level (default for all modules) and the module(s) language level 回答2: Make sure that, in the Project Structure page, you

What is the diamond operator in Java? [duplicate]

最后都变了- 提交于 2019-11-26 03:44:37
问题 This question already has answers here : What is the point of the diamond operator (<>) in Java 7? (7 answers) Closed 6 years ago . I have an arraylist with type patient_class and the arraylist type has been underlined in yellow and the IDE has mentioned \"redundant type arguments in new expression (use diamond operator instead)\". My problem is: Should I use the diamond operator instead? Is it a must? Will I get any data loss or any other problem when storing records to the arraylist? Here

What is the point of the diamond operator (<>) in Java 7?

六眼飞鱼酱① 提交于 2019-11-25 22:14:55
问题 The diamond operator in java 7 allows code like the following: List<String> list = new LinkedList<>(); However in Java 5/6, I can simply write: List<String> list = new LinkedList(); My understanding of type erasure is that these are exactly the same. (The generic gets removed at runtime anyway). Why bother with the diamond at all? What new functionality / type safety does it allow? If it doesn\'t yield any new functionality why do they mention it as a feature? Is my understanding of this