deep-linking

How to use putExtra to open another app and send some data for it?

六月ゝ 毕业季﹏ 提交于 2020-02-21 14:00:09
问题 I have two apps (A, B) that I want to link them together. When the user is in app A, by clicking on a button I want to open app B and send some data to it. I used this method in app A to go app B and send some data to app B: public static boolean openApp(Context mContext, String packageName) { PackageManager manager = context.getPackageManager(); Intent goToEncyclopedia = manager.getLaunchIntentForPackage(packageName); if (goToEncyclopedia == null) { return false; } goToEncyclopedia

How to use putExtra to open another app and send some data for it?

对着背影说爱祢 提交于 2020-02-21 13:49:32
问题 I have two apps (A, B) that I want to link them together. When the user is in app A, by clicking on a button I want to open app B and send some data to it. I used this method in app A to go app B and send some data to app B: public static boolean openApp(Context mContext, String packageName) { PackageManager manager = context.getPackageManager(); Intent goToEncyclopedia = manager.getLaunchIntentForPackage(packageName); if (goToEncyclopedia == null) { return false; } goToEncyclopedia

How to use putExtra to open another app and send some data for it?

不羁岁月 提交于 2020-02-21 13:46:36
问题 I have two apps (A, B) that I want to link them together. When the user is in app A, by clicking on a button I want to open app B and send some data to it. I used this method in app A to go app B and send some data to app B: public static boolean openApp(Context mContext, String packageName) { PackageManager manager = context.getPackageManager(); Intent goToEncyclopedia = manager.getLaunchIntentForPackage(packageName); if (goToEncyclopedia == null) { return false; } goToEncyclopedia

How to use putExtra to open another app and send some data for it?

邮差的信 提交于 2020-02-21 13:45:29
问题 I have two apps (A, B) that I want to link them together. When the user is in app A, by clicking on a button I want to open app B and send some data to it. I used this method in app A to go app B and send some data to app B: public static boolean openApp(Context mContext, String packageName) { PackageManager manager = context.getPackageManager(); Intent goToEncyclopedia = manager.getLaunchIntentForPackage(packageName); if (goToEncyclopedia == null) { return false; } goToEncyclopedia

Android deep linking - Back stack

旧巷老猫 提交于 2020-02-18 07:38:33
问题 I am trying to implement deep linking in my Android application. I have been following this guide. I have an Android Activity that is started from and intent-filter in the Android manifest: <activity android:name=".MyActivity" android:parentActivityName=".MainActivity" > <intent-filter android:label="@string/filter_title_deep_link"> <action android:name="android.intent.action.VIEW" /> <category android:name="android.intent.category.DEFAULT" /> <category android:name="android.intent.category

How to show my app in chooser apps when someone clicks firebase dynamic link?

折月煮酒 提交于 2020-02-07 03:38:25
问题 How should be my android manifest file if I want to show my app in the chooser apps if someone clicks the dynamic link? The URL prefix is like - https://testapp.page.link. At that stage if someone clicks the link then it first opens the browser then it redirects to my app. But I want to show my app in the chooser app list. At this time my manifest file is like follows- <activity android:name=".extraActivities.DynamicLinkActivity"> <intent-filter> <action android:name="android.intent.action

Getting class not found exception when doing deeplinking in xamarin forms

非 Y 不嫁゛ 提交于 2020-01-24 22:46:19
问题 I am trying to add deeplinking feature to my project. My code in Androidmanifest.xml <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" android:versionCode="1" android:versionName="1.0" package="com.companyname.sample"> <uses-sdk android:minSdkVersion="15" /> <application android:label="sample.Android"> <activity android:icon="@drawable/icon" android:name="sample.Droid.MainActivity" android:label="sample"> <intent-filter> <data android

Deeplink: go-back to browser from myApp, after clicking back-button in android, react-native

杀马特。学长 韩版系。学妹 提交于 2020-01-24 00:58:40
问题 I am using Android app, which is openned from chrome using Deeplink , 1) Code of AndroidManifest.xml file, which opens myApp(React-Native) when I click deeplink in browser. <intent-filter android:label="@string/app_name"> <data android:scheme="myapp" android:host="myhost" /> </intent-filter> 2) url-link of browser, which opens app, by matching scheme://host, and I am passing URL's too, as: <a href= "myapp://myhost/?name=gd">Open myApp</a> 3) I am using React-native, for getting those params

Android Deeplink with facebook not working - redirecting to play store instead of launching application

和自甴很熟 提交于 2020-01-23 03:54:05
问题 I am trying to deep link my application with facebook. My App Url is https:www.xyz.com/app Below is my intent filter: <intent-filter android:label="@string/app_name"> <action android:name="android.intent.action.VIEW" /> <category android:name="android.intent.category.BROWSABLE"/> <category android:name="android.intent.category.DEFAULT" /> <data android:scheme="https" android:host="www.xyz.com"/> </intent-filter> I am posting a link in facebook, when someone click on the link, the link is

Ajax deep linking? [closed]

a 夏天 提交于 2020-01-22 12:42:28
问题 As it currently stands, this question is not a good fit for our Q&A format. We expect answers to be supported by facts, references, or expertise, but this question will likely solicit debate, arguments, polling, or extended discussion. If you feel that this question can be improved and possibly reopened, visit the help center for guidance. Closed 7 years ago . I have made a flex app deep link before but now I want to make an ajax app deep link. I have no idea where to start. I assume I need a