decimalformat

I am quite confused about this peculiar 'error' I am getting when parsing a String to a Double. I've already set up the NumberFormat properties and symbols. When passing a String with 15 digits and 2 decimals (ex. str = "333333333333333,33" ) and parsing it with Number num = NumberFormat.parse(str) the result is omitting a digit. The actual value of num is 3.333333333333333E14 . It seems to be working with Strings with all 1's, 2's and 4's though... Anyone can enlighten me? Cheers Enrico The short answer; due to round error (double) 111111111111111.11 != (double) 111111111111111.1 but (double)

I need to set a mask for a textview to convert its text to a specific style (Currency, my own though Like this: Rls ###,###,###,### ) but I need to be able to get it's raw text later on. What shall I do? ====================================================== say I will pass this string to the TextView: 2120000 It should be seen by user like : Rls 2,120,000 but the .getText method should return: 2120000 ====================================================== the formatting code would be like this: DecimalFormatSymbols symbols = new DecimalFormatSymbols(); symbols.setDecimalSeparator(',');

The input looks like 8.7000000 and I want to format it to look like 8.70 EUR . I considered using the DecimalFormat class: Double number = Double.valueOf(text); DecimalFormat dec = new DecimalFormat("#.## EUR"); String credits = dec.format(number); TextView tt = (TextView) findViewById(R.id.creditsView); tt.setText(credits); The result is 8.7 EUR . How can I tell the formatter to have two digits after the . ? Matt Fellows Also want to highlight here Jon Skeet's point about using integers to store all your currency - don't want to be dealing with floating-point rounding errors with money. Use

I'm trying to format a string to add commas between 3 digit groups EG: 1200.20 >> 1,200.20 15000 >> 15,000 I'm trying to figure out how to do it with DecimalFormat, to this point I have been using a script of my own that seems overly complicated. I cannot figure out how to do it, using # simply hides trailing zeroes and using 0 adds them to the number. This is what I'm trying right now: DecimalFormat df = new DecimalFormat("###,###.####", new DecimalFormatSymbols(Locale.US)); resultStr = df.format(Double.valueOf(resultStr)); I'm sure it must be easy but I'm not sure how to do it. I don't have