decimalformat

问题 This question already has answers here : How can I format a String number to have commas and round? (10 answers) Number formatting in java to use Lakh format instead of million format (3 answers) Closed 5 years ago . I want to obtain number in following format: 1000 = 1,000 10000 = 10,000 100000 = 1,00,000 I tried this: import java.text.DecimalFormat; public class StringProcessingDemo { public static void main(String[] args) { String pattern = "##,##,###.###"; DecimalFormat myFormatter = new

问题 I want to format a number by a given format string using DecimalFormat . This is documented in the oracle java docs. public class DecimalFormatDemo { static public void customFormat(String pattern, double value ) { DecimalFormat myFormatter = new DecimalFormat(pattern); String output = myFormatter.format(value); System.out.println(value + " " + pattern + " " + output); } static public void main(String[] args) { customFormat("###,###.###", 123456.789); } } But my output is German format style

问题 Having a big problem with json_encode it automatically round off the digits but I need 2 decimal points on every digits. PHP: <?php $numbers = [1.00,2.00]; foreach ($numbers as $i => $number) { $numbers[$i] = number_format($number, 2, '.', null); } echo json_encode($numbers, JSON_NUMERIC_CHECK); ?> OUTPUT: [1,2] EXPECTED OUTPUT: [1.00,2.00] how can I prevent every digits for not rounding off automatically? PS: NOT A STRING :) 回答1: Sounds like you are looking for JSON_PRESERVE_ZERO_FRACTION,

问题 I am using DecimalFormat to create a formated decimal that is always 6 characters long. At first I used the format string of new DecimalFormat("000.00") but this gave me a bug for negative numbers. The minus sign is added and makes the number one space larger resulting in -005.25 and not -05.25 as desired. I have been able to fix this with the following code DecimalFormat fmt; if(netAmt < 0){ fmt = new DecimalFormat("00.00"); }else{ fmt = new DecimalFormat("000.00"); } System.out.println(fmt

问题 I'm using DecimalFormat to format doubles into a String. This String is then integrated into my presentation layer. Problem : I want to keep ALL decimals. Example: "12345678.123456789" Question : What format should I use? Remark : I use a different Locale to support multiple layouts. Format: #.## -> This uses ALL numbers BEFORE the decimal, but ROUNDS the numbers AFTER the decimal. I could use #.######### for the big decimal, but what if the decimal is even longer? I found my small test

问题 I've used DecimalFormat df = new DecimalFormat("#,###.00"); to format a BigDecimal . Now, I want to use that formatted value (say it is '1 250,00') to create new BigDecimal . I've tried this: BigDecimal result = new BigDecimal(model.getValue().replace(",",".").replace(" ","")); But that space between 1 and 2 in 1 250.00 is not replaced. How can I fix it? Example: DecimalFormat df = new DecimalFormat("#,###.00"); BigDecimal example = new BigDecimal("1250"); String str = df.format(example);

问题 I'm trying to format a string to add commas between 3 digit groups EG: 1200.20 >> 1,200.20 15000 >> 15,000 I'm trying to figure out how to do it with DecimalFormat, to this point I have been using a script of my own that seems overly complicated. I cannot figure out how to do it, using # simply hides trailing zeroes and using 0 adds them to the number. This is what I'm trying right now: DecimalFormat df = new DecimalFormat("###,###.####", new DecimalFormatSymbols(Locale.US)); resultStr = df

问题 How would I convert the following code to C# DecimalFormat form String pattern = ""; for (int i = 0; i < nPlaces - nDec - 2; i++) { pattern += "#"; } pattern += "0."; for (int i = nPlaces - nDec; i < nPlaces; i++) { pattern += "0"; } form = (DecimalFormat) NumberFormat.getInstance(); DecimalFormatSymbols symbols = form.getDecimalFormatSymbols(); symbols.setDecimalSeparator('.'); form.setDecimalFormatSymbols(symbols); form.setMaximumIntegerDigits(nPlaces - nDec - 1); form.applyPattern(pattern)

问题 is there a class in Java that lets you format a number like "102203345.32" to this "102.203.345,32" and return a string type? I would like to obtain a String where the thousands are separated by the '.' and the decimals are separated by a comma ','. Could someone help me please? I found a class DecimalFormat and I tried to customize it: public class CustomDecimalFormat { static public String customFormat(String pattern, double value ) { DecimalFormat myFormatter = new DecimalFormat(pattern);

问题 I am quite confused about this peculiar 'error' I am getting when parsing a String to a Double. I've already set up the NumberFormat properties and symbols. When passing a String with 15 digits and 2 decimals (ex. str = "333333333333333,33" ) and parsing it with Number num = NumberFormat.parse(str) the result is omitting a digit. The actual value of num is 3.333333333333333E14 . It seems to be working with Strings with all 1's, 2's and 4's though... Anyone can enlighten me? Cheers Enrico 回答1: